A house is losing heat at a rate of 1800 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per ( a ) K. ( b ) °F, and ( c ) R difference between the indoor and the outdoor temperature.

Question

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Answer 1

Textbook Question

Chapter 1.11, Problem 94RP

A house is losing heat at a rate of 1800 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per (a) K. (b) °F, and (c) R difference between the indoor and the outdoor temperature.

(a)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

(b)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

(c)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

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Answer 2

Textbook Question

Chapter 1.11, Problem 94RP

A house is losing heat at a rate of 1800 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per (a) K. (b) °F, and (c) R difference between the indoor and the outdoor temperature.

(a)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

(b)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

(c)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

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Answer 3

Textbook Question

Chapter 1.11, Problem 94RP

A house is losing heat at a rate of 1800 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per (a) K. (b) °F, and (c) R difference between the indoor and the outdoor temperature.

(a)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

(b)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

(c)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

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Answer 4

Textbook Question

Chapter 1.11, Problem 94RP

A house is losing heat at a rate of 1800 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per (a) K. (b) °F, and (c) R difference between the indoor and the outdoor temperature.

(a)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

(b)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

(c)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

(b)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

(c)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

Answer 8

(a)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale.

Answer 13

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Answer 14

Explanation of Solution

Refer Figure 1.13.

Write the expression of magnitude of temperature unit.

ΔT(K)=ΔT(°C) (I)

Since the temperature of a system is rising during hyperthermia, the temperature in Kelvin and Celsius unit are identical.

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(°C) in Equation (I).

ΔT(K)=1800 kJ/h per °C=1800 kJ/h per K

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Kelvin scale is 1800 kJ/h per K_.

Answer 15

(b)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale.

Answer 20

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Answer 21

Explanation of Solution

Write the expression of conversion relation between K to °F.

ΔT(°F)=ΔT(K)×1.8 (II)

Conclusion:

Substitute 1800 kJ/h per °C for ΔT(K) in Equation (II).

ΔT(°F)=(1800 kJ/h per °C)×1.8=1000 kJ/h per °F

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Fahrenheit scale is 1000 kJ/h per °F_.

Answer 22

(c)

Expert Solution

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

The rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale.

Answer 27

Answer to Problem 94RP

The rate of heat loss from a house is 1800 kJ/h per °C in Rankine scale is 1000 kJ/h per R_.

Answer 28

Explanation of Solution

Write the expression of conversion relation between K to R.

ΔT(R)=ΔT(K)×1.8 (III)

Conclusion:

Substitute 3K for ΔT(K) in Equation (III).

ΔT(R)=1800 kJ/h per °C×1.8=1800 kJ/h per R

Thus, the rate of heat loss from a house is 1800 kJ/h per °C express in Rankine scale is 1000 kJ/h per R_.

Answer 29

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A house is losing heat at a rate of 1800 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Express the rate of heat loss from this house per ( a ) K. ( b ) °F, and ( c ) R difference between the indoor and the outdoor temperature.

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Answer to Problem 94RP

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Answer to Problem 94RP

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Answer to Problem 94RP

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