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Interpretation: The geometry for carbocations and carbanions has to be predicted
Concept Introduction: According to VSEPR (Valence Shell Electron Pair Repulsion) theory, each molecule gets a unique structure. That structure is explained by considering steric number of that molecule.
The steric number is the combination of both number of σ-bonds and number of lone pairs involved in a particular molecule.
σ-bonds are formed by the mutual sharing of electrons between the two atoms. As a result, bond between two atoms is formed. This type of bond is called covalent bond. In this process, bonding electron pairs are involved.
Non-bonding electrons are not involved in the bond formation. They are called lone pairs.
The geometry of the atom will be determined by counting the steric number followed by the hybridization state of that atom and finally electronic arrangement of atoms in space.
If the steric number is 4, the atom or ion has sp3 hybridization and the electronic arrangement of atoms in space (i.e. geometry) will be tetrahedral.
If the steric number is 3, the atom or ion has sp2 hybridization and the electronic arrangement of atoms in space (i.e. geometry) will be trigonal planar.
If the steric number is 2, the atom or ion has sp hybridization and the electronic arrangement of atoms in space (i.e. geometry) will be linear.
To find: Comparing the structures of carbocation and carbanion and assigning the correct geometry to each ion
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Chapter 1 Solutions
ORGANIC CHEMISTRY-STD.WILEY PLUS CARD
- Don't used hand raiting and don't used Ai solutionarrow_forwardDon't used Ai solution and don't used hand raitingarrow_forwardOA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forward
- Don't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardQ3: Arrange each group of compounds from fastest SN2 reaction rate to slowest SN2 reaction rate. CI Cl H3C-Cl CI a) A B C D Br Br b) A B C Br H3C-Br Darrow_forwardQ4: Rank the relative nucleophilicity of halide ions in water solution and DMF solution, respectively. F CI Br | Q5: Determine which of the substrates will and will not react with NaSCH3 in an SN2 reaction to have a reasonable yield of product. NH2 Br Br Br .OH Brarrow_forward
- Classify each molecule as optically active or inactive. Determine the configuration at each H соон Chirality center OH 애 He OH H3C Ноос H H COOH A K B.arrow_forwardQ1: Rank the relative nucleophilicity of the following species in ethanol. CH3O¯, CH3OH, CH3COO, CH3COOH, CH3S Q2: Group these solvents into either protic solvents or aprotic solvents. Acetonitrile (CH3CN), H₂O, Acetic acid (CH3COOH), Acetone (CH3COCH3), CH3CH2OH, DMSO (CH3SOCH3), DMF (HCON(CH3)2), CH3OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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