BIO Peak Pedaling Torque The downward force produced by the quadriceps muscles during the power stroke of bicycle-pedaling motion is shown in Figure 11-67 as a function of the crank angle ϕ (see Figure 11-39 .The force from these muscles decreases linearly, but the torque depends on the crank angle according to τ = rF sin (180° − ϕ ). Use the information in the graph, together with a computer spreadsheet to find the angle ϕ at which the pedaling torque produced by the quadriceps muscle is a maximum. (Note that the actual torque applied to the crank is a result of the action of many muscles in addition to the quadriceps). Figure 11-67 Problem 89
BIO Peak Pedaling Torque The downward force produced by the quadriceps muscles during the power stroke of bicycle-pedaling motion is shown in Figure 11-67 as a function of the crank angle ϕ (see Figure 11-39 .The force from these muscles decreases linearly, but the torque depends on the crank angle according to τ = rF sin (180° − ϕ ). Use the information in the graph, together with a computer spreadsheet to find the angle ϕ at which the pedaling torque produced by the quadriceps muscle is a maximum. (Note that the actual torque applied to the crank is a result of the action of many muscles in addition to the quadriceps). Figure 11-67 Problem 89
BIO Peak Pedaling Torque The downward force produced by the quadriceps muscles during the power stroke of bicycle-pedaling motion is shown in Figure 11-67 as a function of the crank angle ϕ (see Figure 11-39.The force from these muscles decreases linearly, but the torque depends on the crank angle according to τ = rFsin (180° − ϕ). Use the information in the graph, together with a computer spreadsheet to find the angle ϕ at which the pedaling torque produced by the quadriceps muscle is a maximum. (Note that the actual torque applied to the crank is a result of the action of many muscles in addition to the quadriceps).
In the Donkey Kong Country video games you often get around by shooting yourself out of barrel cannons. Donkey Kong wants to launch out of one barrel and land in a different one that is a distance in x of 9.28 m away. To do so he launches himself at a velocity of 22.6 m/s at an angle of 30.0°. At what height does the 2nd barrel need to be for Donkey Kong to land in it? (measure from the height of barrel 1, aka y0=0)
For which value of θ is the range of a projectile fired from ground level a maximum?
90° above the horizontal
45° above the horizontal
55° above the horizontal
30° above the horizontal
60° above the horizontal
A map from The Legend of Zelda: The Breath of the Wild shows that Zora's Domain is 7.55 km in a direction 25.0° north of east from Gerudo Town. The same map shows that the Korok Forest is 3.13 km in a direction 55.0° west of north from Zora's Domain. The figure below shows the location of these three places. Modeling Hyrule as flat, use this information to find the displacement from Gerudo Town to Korok Forest. What is the magnitude of the displacement? Find the angle of the displacement. Measure the angle in degrees north of east of Gerudo Town.
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