The amount of Sucrose required to prepare 1 .0 L aqueous solution of Sucrose has to be calculated. Concept Introduction: When a semipermeable membrane, separates a solution and pure solvent. The solvent molecules are passed through the semi permeable membrane. There is gradual increase in the volume of solution with a decrease in volume of the solvent with respect to time. The flow of solvent through a semipermeable membrane into the solution is called as osmosis. By the time system reaches equilibrium, the changes in the liquid level stops. There is a higher hydrostatic pressure on the solution than compared to that of the pure solvent because there is variation in the liquid levels at this point. The excess pressure on the solution is called osmotic pressure. The osmotic pressure of solution is calculated by using, π =MRT Here, π = osmotic pressure(in atm) M=molarity of solution(in M) R= Gas Law constant L atm T=Temperature(in K)
The amount of Sucrose required to prepare 1 .0 L aqueous solution of Sucrose has to be calculated. Concept Introduction: When a semipermeable membrane, separates a solution and pure solvent. The solvent molecules are passed through the semi permeable membrane. There is gradual increase in the volume of solution with a decrease in volume of the solvent with respect to time. The flow of solvent through a semipermeable membrane into the solution is called as osmosis. By the time system reaches equilibrium, the changes in the liquid level stops. There is a higher hydrostatic pressure on the solution than compared to that of the pure solvent because there is variation in the liquid levels at this point. The excess pressure on the solution is called osmotic pressure. The osmotic pressure of solution is calculated by using, π =MRT Here, π = osmotic pressure(in atm) M=molarity of solution(in M) R= Gas Law constant L atm T=Temperature(in K)
Solution Summary: The author explains how the amount of Sucrose required to prepare aqueous solution is calculated. The flow of solvent through the semipermeable membrane is called osmosis.
Interpretation: The amount of Sucrose required to prepare
1.0L aqueous solution of Sucrose has to be calculated.
Concept Introduction:
When a semipermeable membrane, separates a solution and pure solvent. The solvent molecules are passed through the semi permeable membrane. There is gradual increase in the volume of solution with a decrease in volume of the solvent with respect to time. The flow of solvent through a semipermeable membrane into the solution is called as osmosis. By the time system reaches equilibrium, the changes in the liquid level stops. There is a higher hydrostatic pressure on the solution than compared to that of the pure solvent because there is variation in the liquid levels at this point. The excess pressure on the solution is called osmotic pressure.
The osmotic pressure of solution is calculated by using,
9:27 AM Tue Mar 4
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Problem 64 of 15
#63%
Submit
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product
structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s).
Be sure to account for all bond-breaking and bond-making steps.
0:0
0:0
:0:
N.
:0:
:O
:0:
H
H.
:0:
Select to Add Arrows
O
:0:
H
O
:0:
0:0.
S.
H
Select to Add Arrows
S
:0:
:0:
H
H
Order the following organic reactions by relative rate. That is, select '1' next to the reaction that will have the fastest initial rate, select '2' next to the reaction
that will have the next fastest initial rate, and so on. If two reactions will have very similar initial rates, you can select the same number next to both.
If a reaction will have zero or nearly zero initial rate, don't select a number and check the box in the table instead.
Note: the "Nu" in these reactions means "a generic nucleophile."
ملی
CI
:Nu
2
он
3
H
Reaction
Relative Rate
(Choose one) ▼
Nu
:CI:
zero or nearly zero
Nu
:Nu
bi
(Choose one)
zero or nearly zero
: Nu
لی
Nu
:H
(Choose one)
zero or nearly zero
9:12 AM Tue Mar 4
66%
Problem 38 of 15
Submit
Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow
the arrows to draw the product formed in this reaction or mechanistic step(s).
Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.
Br2
FeBrз
H
(+)
Br:
H
: Br----FeBr3
く
a
SU
00
nd
e