Chapter 11, Problem 66P

To determine

To Calculate: The wavelength of electromagnetic waves.

Answer to Problem 66P

  $2\times {10}^{-2}\text{m}$

Explanation of Solution

Given Information:

The length of the satellite dish = $0.5\text{m}$

An error allowed in the direction of the satellite dish= $2°$

Concept used:

  $\begin{array}{l}\mathrm{\phi }=\frac{\mathrm{\lambda }}{\mathrm{l}}\\ \mathrm{\lambda }=\mathrm{\phi }\mathrm{l}\end{array}$

Here,

  $\mathrm{\phi }$ is the error in the direction,

  $\mathrm{\lambda }$ is wavelength of wave,

  $\mathrm{l}$ is diameter of dish.

Calculation:

  $\mathrm{\lambda }=\mathrm{\phi }\mathrm{l}$

  $\begin{array}{l}\mathrm{\lambda }=(2°\times \frac{\mathrm{\pi }}{180°})\times 0.5\text{m}\\ \mathrm{\lambda }=2\times {10}^{-2}\text{m}\end{array}$

Conclusion: The wavelength of the satellite dish is $2\times {10}^{-2}\text{m}$ .