Chapter 11, Problem 28P

(a)

To determine

To Find: The period.

Answer to Problem 28P

The period of a pendulum is $1.7\text{ s/cycle}$ .

Explanation of Solution

Given:

Number of vibrations, $\text{N= }36$

Time, $t=60\text{ s}$

Formula used:

The period of a pendulum is determined by the following formula,

  $T\text{ = }\frac{t}{\text{N}}$

Calculation:

Substitute the given values in the above formula,

  $T=\frac{60}{36}=1.7\text{ s / cycle}$

Conclusion:

Thus, the period of a pendulum is $1.7\text{ s/cycle}$ .

(b)

To determine

To Find: The frequency.

Answer to Problem 28P

The frequency of a pendulum is $0.59\text{ Hz}$ .

Explanation of Solution

Given:

Period, $T=1.7\text{ s/cycle}$

Formula used:

Frequency of a pendulum is determined by the following formula,

  $f\text{ = }\frac{\text{1}}{\text{ (}T\text{)}}$

Calculation:

Substitute the given values in the above formula,

  $f=\frac{1}{1.7}=0.59\text{ Hz}$

Conclusion:

Thus, the frequency of a pendulum is $0.59\text{ Hz}$ .