
Concept explainers
(a)
To Find: The amplitude.
(a)

Answer to Problem 22P
The amplitude of A wave is
Explanation of Solution
Given:
Graph is given in the equation.
Formula used:
A wave and B wave intersects at y axis, the point of intersection will give us the amplitude of A wave and B wave respectively.
Calculation:
By identifying these two wave, amplitude of A wave is
Conclusion:
Thus, the amplitude of A wave is
(b)
To Find: The frequency.
(b)

Answer to Problem 22P
The frequency of A wave is
Explanation of Solution
Given:
Completion time of 1 cycle for both the wave is easily identified from the graph.
A wave takes 4 seconds to complete 1 cycle (TA= 4 sec).
B wave takes 2 seconds to complete 1 cycle (TB= 2 sec).
Formula used:
The relationship between the period and frequency is,
Calculation:
From the above equation,
Frequency of A wave
Frequency of B wave
Conclusion:
Thus, the frequency of A wave is
(c)
To Find: The period.
(c)

Answer to Problem 22P
The period of A wave is
Explanation of Solution
Given:
Graph is given for A and B.
Formula used:
The period of any wave is the amount of time taken to complete one cycle.
Calculation:
From the graph, it is clearly visible that the period of wave A and wave B is 4 seconds and 2 seconds respectively.
Conclusion:
Thus, the period of A wave is
(d)
To Derive: The equation in the form of sine and cosine.
(d)

Answer to Problem 22P
The equation for the wave A is
Explanation of Solution
Given:
Amplitude of wave
Amplitude of wave
Frequency of wave A
Frequency of wave B
Formula used:
Displacement is a function of time, which is represented by following two way.
Calculation:
Wave A has zero displacement at time t = 0, so it is having sine function and it is as follows.
Wave B has maximum displacement at time t = 0, so it is having cosine function and it is as follows.
Conclusion:
Thus, the equation for the wave A is
Chapter 11 Solutions
Physics: Principles with Applications
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