Chapter 11, Problem 62P

To determine

To Calculate: The speed of the wave in the second medium.

Answer to Problem 62P

The speed of the wave in the second wave is $10.2\text{km/s}$ .

Explanation of Solution

Given Information:

The velocity of the wave in the first medium, $v_1=8\text{km/s}$

Angle of incidence, ${\phi }_1=47°$

Angle of refraction, ${\phi }_2=35°$

Formula used:

According to Snell’s law:

  $\frac{v_1}{v_2}=\frac{\sin ({\phi }_2)}{\sin ({\phi }_1)}$

Where, $v_1$ and $v_2$ are the velocities of the wave in the first and second medium.

Calculation:

From Snell’s law

  $v_2=\frac{\sin ({\phi }_1)v_1}{\sin ({\phi }_2)}$

  $v_2$ = $8\left(\frac{\sin 47°}{\sin 35°}\right)$

  $v_2$ = $10.2\text{km/s}$

Conclusion: The speed of the sound wave in the second medium is $10.2\text{km/s}$ .