Chapter 11, Problem 31E

Interpretation Introduction

Interpretation:

For different units, the pressure is to be converted.

Concept introduction:

There are several units of pressure.

$\text{atm}$, $\text{mm Hg}$, $\text{kPa}$ and $\text{torr}$ are the units of pressure.

$1\text{ mm Hg}$ is equal to $\text{0}\text{.03937 in}\text{. Hg}$.

$1\text{ atm}$ is equal to $\text{29}\text{.92 in}\text{. Hg}$.

$1\text{ kPa}$ is equal to $\text{0}\text{.29529 in}\text{. Hg}$.

$\text{0}\text{.03937 in}\text{. Hg}=\text{1 torr }$