Chapter 11, Problem 126E

Interpretation Introduction

Interpretation: The mass of air in air-filled tire and the mass of helium in helium-filled tire is to be calculated. The mass difference between the two is to be determined.

Concept Introduction: The mass of $\text{1 mol}$ of atoms for an element is known as its molar mass.

The equation of ideal gas law is written as:

$PV=nRT$

Here, $R$ is the ideal gas constant.

The relation between $\text{atm}$ and $\text{psi}$ is:

$\text{1 atm}=14.69\text{ psi}$

The relation between $\text{milliliter}$ and $\text{liter}$ is:

$\text{1 mL}={10}^{-3}\text{ L}$