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(a)
Interpretation:
Identify the intermolecular forces that must be overcome to perform the following statement of melt ice.
Concept Introduction:
London dispersion force also called an induced dipole-induced dipole attraction is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.
Dipole-dipole interaction results when two dipolar molecules interact with each other through space, there occurs a partially negative charge of one of the polar molecules is attracted to the partially positive charge of the second polar molecule.
Ion-dipole interaction results of an electrostatic interaction between a charged ion and a molecule that has a dipole.
A hydrogen bonding is partially an electrostatic attraction between
(a)
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Answer to Problem 1PS
In ice the water molecules are held together by hydrogen bonding network to from a three dimensional lattice.
Explanation of Solution
In water molecules the hydrogen bond in ice are linear and have strong directional property, this directionality indicate that hydrogen bonds in ice are as strong as a covalent bond. During melting few of these hydrogen bonds are melting to from water.
In water a
(b).
Interpretation:
Identify the intermolecular forces that must be overcome to perform the following statement of sublime solid of iodine.
Concept Introduction:
London dispersion force also called an induced dipole-induced dipole attraction is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.
Dipole-dipole interaction results when two dipolar molecules interact with each other through space, there occurs a partially negative charge of one of the polar molecules is attracted to the partially positive charge of the second polar molecule.
Ion-dipole interaction results of an electrostatic interaction between a charged ion and a molecule that has a dipole.
A hydrogen bonding is partially an electrostatic attraction between
(b).
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Answer to Problem 1PS
Iodine molecules are non-polar, only dispersion forces must be overcome.
Explanation of Solution
They sublime because though there are covalent bonds within molecule holding two iodine atoms together.
From this molecule Van der Waal’s forces are very weak interactions between molecules of a substance hence the iodine molecules easily escape from the solid structure easily.
(c)
Interpretation:
Identify the intermolecular forces that must be overcome to perform the following statement of convert liquid
Concept Introduction:
London dispersion force also called an induced dipole-induced dipole attraction is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.
Dipole-dipole interaction results when two dipolar molecules interact with each other through space, there occurs a partially negative charge of one of the polar molecules is attracted to the partially positive charge of the second polar molecule.
Ion-dipole interaction results of an electrostatic interaction between a charged ion and a molecule that has a dipole.
A hydrogen bonding is partially an electrostatic attraction between
(c)
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Answer to Problem 1PS
Ammonia vaporization having hydrogen bonding was occurred.
Explanation of Solution
Ammonia is a polar molecule since the nitrogen atom is more electronegative than hydrogen, and the only intermolecular forces present are London dispersion force was occurred.
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Chapter 11 Solutions
Chemistry & Chemical Reactivity
- Estimate the DH°rxn of the reaction below: H H-C-C=C-H H Н A table of bond energy Bond H Bond Energy (kJ/mol) C-H 413 C-O 360 C=O 743 C-C 348 |C = C 612 O-H 463 H-H 436 + H-H -> H H-C. - H | | 1 HHHarrow_forwardShow work...don't give Ai generated solutionarrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 3A(g) + 1B (g) 4C (g) + 7D (g) Substance AH in kJ/mol A (g) - 25.07 B (g) - 36.51 C (g) - 90.09 D (g) + 56.11 AHran =?kJarrow_forward
- What is the change in internal energy (ΔU) when a system is heated with 42.0 J of energy while it does 110.0 J of work?arrow_forwardCan you help me solve this problem and explain what the answers are?arrow_forwardFor which reaction below does the enthalpy change under standard conditions correspond to a standard enthalpy of formation? (Choose all that applies) SO2(g) + 1/2 O2(g) → SO3(g) 2H2(g) + C(s) → CH4(g) Mg(s) + 1/2 O2(g) → MgO(s) CO(g) + H2O(g) → CO2(g) + H2(g) CO2(g) + H2(g) → CO(g) + H2O(g) 1/2 H2(g) + 1/2 N2(g) + 3/2 O2(g) → HNO3(g) CO2(g) + C(s) 2CO(g) N2(g) + 202(g) → 2NO2(g)arrow_forward
- Choose all the molecules with zero standard-enthalpy-of-formation (AH% = 0) Fe(s) FeCl2(s) N2(g) H2O(l) 02(g) C(graphite) K(s) H2O(g)arrow_forward8.5 g of potassium hydroxide (molar mass = 56.1 g/mol) dissolves in 125 g of water and the temperature of the solution increases by 15.58°C. Calculate the AH soln for potassium hydroxide. Assume the specific heat capacity of the solution is 4.2 J.g¨¹.ºC-1. KOH(s) → →K+ K(aq) + OH AH solution = ?kJ/mol (aq)arrow_forwardWhat will be the final temperature of a 8.79 g piece of iron (CP = 25.09 J/(mol · oC)) initially at 25.0oC, if it is supplied with 302.8 J from a stove?arrow_forward
- Identify the set of stoichiometric coefficients that balances the reaction equation for the combustion of the hydrocarbon below: _ C19 H4002 → CO2 + H2Oarrow_forwardThe cooling system in an automobile holds 11.3 L of ethylene glycol antifreeze. How much energy is absorbed when the temperature of the ethylene glycol goes from 20oC to 100oC? The density and specific heat capacity of ethylene glycol are 1.11 g/mL and 2.42 J/(g ⋅ oC), respectively.arrow_forwardWhich statement about the following chemical reaction is not correct? 2NH3+202 →→→ N2O + 3H₂O ○ It requires 2 mol of ammonia to produce 3 mol of water. It requires 2 mol of dioxygen to produce 1 mol of N2O. ○ Nine moles of water are produced when four moles of ammonia are consumed. Two moles of N2O would be produced when four moles of dioxygen are consumed. Two moles of ammonia react with two moles of dioxygen.arrow_forward
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