The relative numbers of Br 2 molecules in the second and first excited vibrational state has to be calculated at 298K . Concept introduction: The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below. N 2 N 1 = exp ( − h c v ˜ k T )

Question

Want to see the full answer?

Answer 1

Question

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

For the compound: C8H17NO2 Use the following information to come up with a plausible structure: 8 This compound has "carboxylic acid amide" and ether functional groups. The peaks at 1.2ppm are two signals that are overlapping one another. One of the two signals is a doublet that represents 6 hydrogens; the other signal is a quartet that represents 3 hydrogens.

Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling point, choose 2 next to the substance with the next highest boiling point, and so on. substance C D chemical symbol, chemical formula or Lewis structure. CH,-N-CH, CH, H H 10: H C-C-H H H H Cale H 10: H-C-C-N-CH, Bri CH, boiling point (C) Сен (C) B (Choose

Answer 2

Question

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Answer 6

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

Answer 7

Chapter 11, Problem 11C.5BE

(i)

Interpretation Introduction

Interpretation:

The relative numbers of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

The complex vibrations exhibit by the polyatomic molecule is known as normal modes of vibrations. The vibrational modes of a molecule are IR or Raman active. If a molecule has a centre of symmetry, then the modes which are IR-active will be Raman inactive and the modes that are IR-inactive will be Raman active. The relative population at two vibrational states is given by Boltzmann distribution as shown below.

N2N1=exp(−hcv˜kT)

Answer 8

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Answer 9

(ii)

Interpretation Introduction

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 11 - Prob. 11A.1ST Ch. 11 - Prob. 11A.2ST Ch. 11 - Prob. 11B.1ST Ch. 11 - Prob. 11B.2ST Ch. 11 - Prob. 11B.3ST Ch. 11 - Prob. 11B.4ST Ch. 11 - Prob. 11C.1ST Ch. 11 - Prob. 11C.2ST Ch. 11 - Prob. 11D.1ST Ch. 11 - Prob. 11E.1ST

Interpretation: The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K. Concept introduction: As mentioned in the concept of introduction in part (i).

Want to see the full answer?

Chapter 11 Solutions

Interpretation:

The relative number of Br2 molecules in the second and first excited vibrational state has to be calculated at 298K.

Concept introduction:

As mentioned in the concept of introduction in part (i).