Concept explainers
(a)
Interpretation:
The line structure of
Concept Introduction:
Line structure: Line structure is a simplest representation of a hydrocarbon. In line structure, the chain of carbon atoms is shown as a zigzag line. The end of each short line in the zigzag represents a carbon atom. Since the carbon nearly always has a valence of four in organic compounds, it is not necessary to show the hydrogen atoms.
Class of hydrocarbons:
(a)

Answer to Problem 11A.1E
The line structure of
Explanation of Solution
The given condensed formula is
The presence of triple bond in the compound shows that it belongs to alkyne.
(b)
Interpretation:
The line structure of
Concept Introduction:
Refer to part (a).
(b)

Answer to Problem 11A.1E
The line structure of
Explanation of Solution
The given condensed formula is
The presence of single bond in the compound shows that it belongs to alkane.
(c)
Interpretation:
The line structure of
Concept Introduction:
Refer to part (a).
(c)

Answer to Problem 11A.1E
The line structure of
Explanation of Solution
The given condensed formula is
The presence of double bond in the compound shows that it belongs to alkene.
(d)
Interpretation:
The line structure of
Concept Introduction:
Refer to part (a).
(d)

Answer to Problem 11A.1E
The line structure of
In
Explanation of Solution
The given condensed formula is
In
(e)
Interpretation:
The line structure of
Concept Introduction:
Refer to part (a).
(e)

Answer to Problem 11A.1E
The line structure of
Explanation of Solution
The given condensed formula is
The presence of double bonds in the compound shows that it belongs to alkene.
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Chapter 11 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 2TERM
- H-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forwardDraw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forward
- Draw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product basearrow_forwardWhat alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. draw structure ... andarrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward
- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward
- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). H-Br CH2Cl2arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning

