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Concept explainers
(a)
Interpretation:
Small nuclei combining together to form large nucleus is in which nuclear process has to be indicated.
Concept Introduction:
Nuclear reactions can be further classified into two additional types. They are nuclear fusion reaction and nuclear fission reaction. These are used as source of energy.
Nuclear fission reaction is the one in which a large nucleus gets split up into two medium-sized nuclei with more free neutrons and a huge amount of energy. The word “fission” itself mean that it is splitting.
Nuclear fusion reactions are the one in which a large nucleus is formed from two small nucleus with release of huge amount of energy. For a nuclear fusion reaction to occur a very high temperature is required.
(b)
Interpretation:
Two intermediate-sized nuclei produced by splitting of large nucleus is more closely related to which nuclear reaction process has to be given.
Concept Introduction:
Nuclear reactions can be further classified into two additional types. They are nuclear fusion reaction and nuclear fission reaction. These are used as source of energy.
Nuclear fission reaction is the one in which a large nucleus gets split up into two medium-sized nuclei with more free neutrons and a huge amount of energy. The word “fission” itself mean that it is splitting.
Nuclear fusion reactions are the one in which a large nucleus is formed from two small nucleus with release of huge amount of energy. For a nuclear fusion reaction to occur a very high temperature is required.
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Chapter 11 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Add substituents to draw the conformer below (sighting down the indicated bond), then rotate the back carbon to provide the anti staggered conformer. + H3C H Ph H Problem 25 of 30 Drawing Atoms, Bonds and Rings Charges Tap a node to see suggestions H H H Undo Rasat Remove Done Finish update Rotate Submitarrow_forwardwhat temperature does a 50% (mole fraction) of ammonia/water liquid mixture boil at 1 atmarrow_forward1) Suppose 0.1 kg ice at 0°C (273K) is in 0.5kg water at 20°C (293K). What is the change in entropy of the ice as it melts at 0°? To produce the original "water gas" mixture, carbon (in a combustible form known as coke) is reacted with steam: 131.4 kJ + H20(g) + C(s) → CO(g) + H2(g) From this information and the equations in the previous problem, calculate the enthalpy for the combustion or carbon to form carbon dioxide. kindly show me how to solve both parts of the same long problem. Thanksarrow_forward
- we were assigned to dilute 900ppm in to 18ppm by using only 250ml vol flask. firstly we did calc and convert 900ppm to 0.9 ppm to dilute in 1 liter. to begin the experiment we took 0,225g of kmno4 and dissolved in to 250 vol flask. then further we took 10 ml sample sol and dissolved in to 100 ml vol flask and put it in to a spectrometer and got value of 0.145A . upon further calc we got v2 as 50ml . need to find DF, % error (expval and accptVal), molarity, molality. please write the whole report. thank you The format, tables, introduction, procedure and observation, result, calculations, discussion and conclusionarrow_forwardQ5. Predict the organic product(s) for the following transformations. If no reaction will take place (or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state is present for each reaction (think Hammond Postulate). I Br₂ CH3 F2, light CH3 Heat CH3 F₂ Heat Br2, light 12, light CH3 Cl2, light Noarrow_forwardNonearrow_forward
- In the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,arrow_forwardFor a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.arrow_forwardPart V. Label ad match the carbons in compounds Jane and Diane w/ the corresponding peak no. in the Spectra (Note: use the given peak no. To label the carbons, other peak no are intentionally omitted) 7 4 2 -0.13 -0.12 -0.11 -0.10 -0.08 8 CI Jane 1 -0.09 5 210 200 190 180 170 160 150 140 130 120 110 100 -8 90 f1 (ppm) 11 8 172.4 172.0 f1 (ppr HO CI NH Diane 7 3 11 80 80 -80 -R 70 60 60 2 5 -8 50 40 8. 170 160 150 140 130 120 110 100 90 -0 80 70 20 f1 (ppm) 15 30 -20 20 -60 60 -0.07 -0.06 -0.05 -0.04 -0.03 -0.02 -0.01 -0.00 -0.01 10 -0.17 16 15 56 16 -0.16 -0.15 -0.14 -0.13 -0.12 -0.11 -0.10 -0.09 -0.08 -0.07 -0.06 -0.05 -0.04 17.8 17.6 17.4 17.2 17.0 f1 (ppm) -0.03 -0.02 550 106 40 30 20 20 -0.01 -0.00 F-0.01 10 0arrow_forward
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