Chapter 11, Problem 11.43QP

(a)

Interpretation Introduction

Interpretation:

Given compound has to be named using IUPAC nomenclature.

Concept Introduction:

A common nomenclature of naming organic compounds has been developed by IUPAC.  By usage of this nomenclature or rules, memorizing of names of organic compounds is not necessary.

IUPAC rules for naming alkenes:

There are about five rules that has to be followed for naming an alkene and an alkyne.  They are,

• The longest continuous carbon chain in the compound that contains double bond or triple has to be identified.  This is known as parent compound.
• Suffix “–ane” (in name of alkane) is replaced with “-ene” for alkene or “-yne” for alkyne.
• Numbering has to be done so that the lowest number is given to the double or triple bond.
• Naming and numbering has to be given for each atom or group that is attached to the parent chain.  Numbering has to be done in a way that substituents get the least numbering.
• If the alkenes have more than one double bond they are called as alkadienes (two double bonds) or alkatrienes (three double bonds).  Appropriate suffix has to be used depending on the number of multiple bonds present in the compound.

Explanation of Solution

Given compound is,

Longest carbon chain with double bond is found to contain five carbon atoms.  Therefore, the parent alkane is pentane. As a double bond is present, the alkene name is pentene.

Numbering has to be given in a way that the double bond gets the least numbering.  In this case, double bond is present between carbon-1 and carbon-2.  Therefore, the parent alkene is 1-pentene.

The substituent present in the given structure is a methyl group on carbon-3.  Substituents name has to be arranged in the alphabetical order.  Number has to be added before the substituent names which indicate the carbon atom in which it is present.  This gives the name of alkene as 3-methyl-1-pentene.

Longest carbon chain containing double bond is pentane.  Position of double bond is 1-pentene.  Substituents present in the chain are 3-methyl.  IUPAC name of the alkene given is 3-methyl-1-pentene.

(b)

Interpretation Introduction

Interpretation:

Given compound has to be named using IUPAC nomenclature.

Concept Introduction:

Refer part (a).

Explanation of Solution

Given compound is,

Longest carbon chain with double bond is found to contain seven carbon atoms.  Therefore, the parent alkane is heptane. As a double bond is present, the alkene name is heptene.

Numbering has to be given in a way that the double bond gets the least numbering.  In this case, double bond is present between carbon-1 and carbon-2.  Therefore, the parent alkene is 1-heptene.

The substituent present in the given structure is a bromine atom on carbon-7.  Number has to be added before the substituent names which indicate the carbon atom in which it is present.  This gives the name of alkene as 7-methyl-1-heptene.

Longest carbon chain containing double bond is heptane.  Position of double bond is 1-heptene.  Substituents present in the chain are 7-bromo.  IUPAC name of the alkene given is 7-bromo-1-heptene.

(c)

Interpretation Introduction

Interpretation:

Given compound has to be named using IUPAC nomenclature.

Concept Introduction:

Refer part (a).

Explanation of Solution

Given compound is,

Longest carbon chain with double bond is found to contain seven carbon atoms.  Therefore, the parent alkane is heptane. As a double bond is present, the alkene name is heptene.

Numbering has to be given in a way that the double bond gets the least numbering.  In this case, double bond is present between carbon-3 and carbon-4.  Therefore, the parent alkene is 3-heptene.

The substituent present in the given structure is a bromine atom on carbon-5.  Number has to be added before the substituent names which indicate the carbon atom in which it is present.  This gives the name of alkene as 5-bromo-3-heptene.

Longest carbon chain containing double bond is heptane.  Position of double bond is 3-heptene.  Substituents present in the chain are 5-bromo.  IUPAC name of the alkene given is 5-bromo-3-heptene.

(d)

Interpretation Introduction

Interpretation:

Given compound has to be named using IUPAC nomenclature.

Concept Introduction:

A common nomenclature of naming organic compounds has been developed by IUPAC.  By usage of this nomenclature or rules, memorizing of names of organic compounds is not necessary.

IUPAC rules for naming cycloalkenes:

• The number of carbon atoms present in the ring is counted and the name of the alkane that has the same number of carbon atoms is given by adding prefix “cyclo-” to the alkane name.  Suffix “-ane” is changed as “-ene”.
• The double bond that is present in the ring is given always the number 1.
• If the ring is substituted, then the names of the group or atoms have to be placed before the name of cycloalkene.
• If the ring contains more than one substituent, then the numbers has to be used in a way that it gives the lowest position for the substituents following position 1 for the double bond.

Explanation of Solution

Given compound is,

Given compound is found to contain six carbon atoms in a cyclic ring structure.  Therefore, the parent cycloalkane is cyclohexane.  As there is a double bond present in the ring, the parent compound name is cyclohexene.

Numbering has to be given in a way that the double bond gets the least numbering.  In this case, double bond is present between carbon-1 and carbon-2.

The substituents present in the given structure are a tert-butyl group on carbon-1 and a methyl group on carbon-4.  Number has to be added before the substituent names which indicate the carbon atom in which it is present.  This gives the name of compound as 1-tert-butyl-4-methylcyclohexene.

Parent chain is found to be cyclohexene.  Position of double bond is carbon-1.  Substituent present in the chain is 1-tert-butyl-4-methyl.  IUPAC name of the compound given is 1-tert-butyl-4-methylcyclohexene.