(a)
Interpretation:
The electronic configuration of the given element by using the symbol of the previous noble gas is to be stated.
Concept Introduction:
The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electronic configuration. The description of every electron that is moving freely in an orbital is given by the electronic configuration of that atom.
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Answer to Problem 113AP
The electronic configuration of the given element, titanium, is
Explanation of Solution
The electronic configuration of titanium that has
This electronic configuration is shown by using the symbol of the noble gas, argon
(b)
Interpretation:
The electronic configuration of the given element by using the symbol of the previous noble gas is to be stated.
Concept Introduction:
The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electronic configuration. The description of every electron that is moving freely in an orbital is given by the electronic configuration of that atom.
![Check Mark](/static/check-mark.png)
Answer to Problem 113AP
The electronic configuration of the given element, selenium, is
Explanation of Solution
The electronic configuration of selenium that has atomic number equal to
This electronic configuration is shown by using the symbol of the noble gas, argon
(c)
Interpretation:
The electronic configuration of the given element by using the symbol of the previous noble gas is to be stated.
Concept Introduction:
The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electronic configuration. The description of every electron that is moving freely in an orbital is given by the electronic configuration of that atom.
The electronic configuration of the given element, antimony, is [ Kr ] 4 d 10 5 s 2 5 p 3 .
The electronic configuration of antimony that has atomic number equal to Z = 51 is shown as,
[ Kr ] 4 d 10 5 s 2 5 p 3
This electronic configuration is shown by using the symbol of the noble gas, krypton [ Kr ] , which has atomic number equal to 36 . The total number of core electrons, that is, 36 possessed by antimony is shown by the symbol of krypton [ Kr ] . The electronic configuration of krypton is 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 10 4 s 2 4 p 6 .
(c)
Interpretation:
The electronic configuration of the given element by using the symbol of the previous noble gas is to be stated.
Concept Introduction:
The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electronic configuration. The description of every electron that is moving freely in an orbital is given by the electronic configuration of that atom.
The electronic configuration of the given element, antimony, is
The electronic configuration of antimony that has atomic number equal to
This electronic configuration is shown by using the symbol of the noble gas, krypton
![Check Mark](/static/check-mark.png)
Answer to Problem 113AP
The electronic configuration of the given element, antimony, is
Explanation of Solution
The electronic configuration of antimony that has atomic number equal to
This electronic configuration is shown by using the symbol of the noble gas, krypton
(d)
Interpretation:
The electronic configuration of the given element by using the symbol of the previous noble gas is to be stated.
Concept Introduction:
The distribution of the electrons that exists in the atomic orbital of an atom is collectively known as electronic configuration. The description of every electron that is moving freely in an orbital is given by the electronic configuration of that atom.
![Check Mark](/static/check-mark.png)
Answer to Problem 113AP
The electronic configuration of the given element, strontium, is
Explanation of Solution
The electronic configuration of strontium that has atomic number equal to
This electronic configuration is shown by using the symbol of the noble gas, krypton
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Chapter 11 Solutions
Introductory Chemistry: Foundation - Text (Looseleaf)
- K m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forwardPlease provide a mechanism of synthesis 1,4-diaminobenzene, start from a benzene ring.arrow_forward
- Consider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forwardNonearrow_forwardCan I get a drawing of what is happening with the orbitals (particularly the p orbital) on the O in the OH group? Is the p orbital on the O involved in the ring resonance? Why or why not?arrow_forward
- 1) How many monochlorination products-including stereochemistry- are there for the molecule below:arrow_forwardSelect an amino acid that has and N-H or O-H bond in its R-group (you have 8 to choose from!). Draw at least two water molecules interacting with the R-group of the amino acid.arrow_forwardIs this aromatic?arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
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