Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 11, Problem 11.19P
To determine
Calculate the hydraulic conductivity of the clay.
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For a laboratory consolidation
test on a clay specimen (drained
both sides), the following were
obtained.
Thickness of the clay layer =
25mm
o_1 = 200KN/m^2
o'2 = 400KN/m^2
e_1 = 0.73
e_2 = 0.61
Time for 50% consolidation (t_50
= 2.8min: From table U = 50%, Tv
= 0.197
%3D
Determine the hydraulic
conductivity (in cm/sec) of the
clay for the loading range.
Subject: Soil Mechanics
Please provide a solution and a diagram
For a laboratory consolidation test on a clay specimen (drained on both sides) the following results were obtained: Thickness of clay soil= 25 mm; P_1 = 50 kPa; P_2 = 120 kPa; e_1 = 0.92; e_2 = 0.78; Time for 50% consolidation= 2.5 min. Tv = 0.197. Determine the hydraulic conductivity of the clay for the loading range in m/min.
a. 1.081 x 10^-3
b. 2.56 x 10^-2
c. 1.31 x 10^-7
d. 1.23 x10 ^-5
Experimental data for clay specimen obtained initial values of e1 = 1.12 and P1 = 90 kPa, and final values of e2 = 0.90 and P2 = 460 kPa
What is the hydraulic conductivity in cm/s if the coefficient of consolidation is 0.036 cm2/s
Chapter 11 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- Question attachedarrow_forwardThe laboratory consolidation test is conducted on a clay sample. The following data results were obtained P1 =55 kPa P2 = 130 kPa e1= 0.95 e2= 0.80 Thickness of the sample of clay= 35mm Time for 50% consolidation = 3.0 min Tv= 0.197 a. Find the coefficient of volume compressibility b. Determine the coefficient of consolidation if a sample of clay was drained on both sides c. Compute the hydraulic conductivity of the clayarrow_forward9. A consolidated drained test was carried out on a sandy clay under a cell pressure of 250 kPa. A constant back pressure of 120 kPa applied throughout the test. The dimensions of the sample were 76 mm x 38 mm. Addional test data recorded at failure were: Load transducer force = 368 N 3 Measured change in volume = 2.42 x 10 m³ Axial deformation = 2.05 mm Determine the major principal stress, o, at failure. (455 kPa)arrow_forward
- A consolidated-undrained tri-axial test was conducted on a normally conslidated clay sample and the results are follows: Chamber confining pressure= 119kpa Deviator Stress at failure=90 kpa Pore water pressure= 58kpa These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 156 kpa. Use stored value. Answer to 5 decimal places.arrow_forwardIn laboratory consolidation tests on a clay specimen (drained on both sides), the following results were obtained:• thickness of clay layer = 25 mm• σ'1 = 50 kN/m2 , e1 = 0.75• σ'2 = 100 kN/m2 , e2 = 0.61• time for 50% consolidation (t50) = 3.1 minDetermine the hydraulic conductivity of the clay for the loading range.arrow_forwardQ.4(a)(i) A laboratory consolidation test on a normally consolidated clay showed the following results: Load, 3( kN/m²) 140 212 Void ratio, e 0.92 0.86 The specimen tested was 25.4 mm in thickness and drained on both sides. The time required for the specimen to reach 50% consolidation was 4.5 min. A similar clay layer in the field 2.8 m thick and drained on both sides is subjected to a similar increase in average effective pressure (i.e. 5o = 140 kN/m² and Jo + 40 = - 212 kN/m²). Determine (a) the expected maximum primary consolidation settlement in the field. (b) the time required for the total settlement in the field to reach 40 mm. [Assume uniform initial increase in excess pore water pressure with depth]arrow_forward
- 3. A consolidated undrained test on a normally consolidated clay yielded the following results: 7.2 psi Pore pressure: Chamber confining pressure: 15 psi 12 psi Calculate the consolidated-undrained friction angle and the drained friction angle. Deviator stress at failure:arrow_forwardA consolidated undrained triaxial test was conducted on a normally consolidated clay sample and the results are as follows: chamber confining pressure = 118 kpa, Deviator stress at failure 93 kpa, pore water pressure = 52 kpa. These results were used to determine the undrained friction angle of the soil. Compute the deviator stress (kPa) at failure when the drain test was conducted in the chamber confining pressure change to 168 kpaarrow_forwardExperimental data for clay specimen obtained initial values of e1 = 1.12 and P1 = 90 kPa, and final values of e2 = 0.90 and P2 = 460 kPa Determine the coefficient of volume compressibilityarrow_forward
- Thanksarrow_forwardA consolidated undrained triaxial test was conducted on a normally consolidated clay. Following are the results of the test: • Cell or Chamber pressure = 200+X kN/m? • Deviator stress at failure = 300+X kN/m? X = 13 a) Determine the consolidated undrained friction angle b) What is the pore water pressure developed in the clay specimen at the end of stage 1 of the test (i.e. consolidation)? c) What is the angle 0 that the failure plane makes with major principal plane? d) Determine the normal stress and shear stress on the failure planearrow_forwardQuestion 2 The result presented in Table Q2a were obtained from a consolidated drained (CD) triaxial test on a normally consolidated clay sample of 75mm height x 38mm diameter tested at a confining pressure of 50 kPa. Table Q2a. CD triaxial test result Axial strain (%) 1 2 5 10 15 Applied force (kN) 0.01 0.03 0.05 0.08 0.10 Page 3 of 6 (a) Draw the Mohr circle for each stress state in the sample and the total stress path (TSP) throughout the test and determine the slope of the TSP to the horizontal.arrow_forward
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