Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 11, Problem 11.10P
(a)
To determine
Calculate the primary consolidation settlement of the clay if the clay is normally consolidated.
(b)
To determine
Calculate the primary consolidation settlement of the clay if the preconsolidation pressure
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Consider the soil profile shown in figure subjected to the uniformly distributed load, Delta sigma = 950 lb/ft^2, on the ground surface. Given: H_1 = 6 ft; H_2 =16 ft; and H_3 = 18ft. Soil characteristics are as follows: Sand: gamma_d = 114 Ib/ft^3, gamma_sat = 118 Ib/ft^3 Clay: gamma_sat = 117 Ib/ft^3; C_c = 0.24; e = 0.69; C_s = C_c/5 Estimate the primary' consolidation settlement in the clay if The clay is normally consolidated The preconsolidation pressure sigma'_c = 2300 Ib/ft^2
a=1
b=5
c=5
d=0
The soil profile shown in Figure 4.2 is subjected to the uniformly distributed load, Ao,
on the ground surface. Given Ao = 15 kN/m2; H1 = 2 m; H2 = 3.5 m; and H3 = 5 m. Soil
characteristics are as follows:
*Sand: ya = 16.5 kN/ms; ysat = 19 kN/m3
*Clay: ysat = 18 kN/m:; LL = 31 %; e = 0.65; Cs = (1/5) C.
Use: Ce= 0.009( LL – 10)
a. Estimate the primary consolidation settlement in the clay (in mm.) if: The
preconsolidation pressure, oc= 621 kN/m2
b. Estimate the value of the void ratio at the end of the primary
consolidation which will be used for the analysis of the secondary consolidation
Aar
O Sand
Clay
Chapter 11 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- EXAMPLE 9.8 A soil profile is shown in Figure 9.24. Given: H₁ Plot the variation of o, u, and o' with depth. H₁ H₂ B Zone of capillary rise G₁ = 2.66; e = 0.55 Degree of saturation = S = 50% Sand Saturated clay = 2 m, H₂ = 1.8 m, H3 = 3.2 m. Rock G₁ = 2.66 e = 0.55 Sand Groundwater table w 42% (moisture content) G₁ = 2.71 Clayarrow_forwardSubject Geotechnical engineering : soil mechanics A layer soil shown has the following data H1= 3m. K1= 2x10^-2 cm/sec H2= 4m K2= 3.2x10^-2 cm/sec H3= 6m K3= 4.1 x 10^ -2 cm/sec Compute the equivalent coefficient of permeability in vertical direction. Compute the velocity if h= 4marrow_forwardConsider the soil profile shown in Figure 11.44 subjected to the uniformly distributed load, Ds, on the ground surface. Given: Ds = 26 kN/m2; H1 = 1.83 m; H2 = 3.66 m; and H3 = 5.5 m. Soil characteristics are as follows: Sand: gdry =17.9 kN/m3; gsat =18.5 kN/m3 Clay: gsat =18.3 kN/m3 ; LL = 38; e = 0.73; Cs = 1/5 Cc Estimate the primary consolidation settlement in the clay if The clay is normally consolidated The preconsolidation pressure s’c = 105 kN/m2arrow_forward
- Subject: Geotechnical engineering- Soil Mechanicsarrow_forward4- Consider the soil profile shown below subjected to the uniformly distributed load, Ao, on the ground surface. Given: Ao = 650 lb/ft²; H1 = 5 ft; H2 = 12 ft; and H; = 18 ft. Soil characteristics are as follows: • Sand: ya = 95 (lb/ft'), Yat = 122 (lb/ft³) • Clay: Yast = 128 (Ib/f²), LL = 38, e = 0.74, Cs = 0.15CC Estimate the primary consolidation settlement in the clay if a) The clay is normally consolidated b) The preconsolidation pressure, o'c= 2,200 lb/ft² Sand Clayarrow_forwardTopic 4:. A soil element is shown in Fig. 1. Determine the following (clearly show calculation procedures): a. Major principal stress b. Minor principal stress c. Normal and shear stress on plane EF d. Use rotation method to locate the normal and shear stress on the plane EF (plot the Mohr's circle by compass and locate normal and shear stress in Fig. 2, 0, = 45 kN/m? y T = 40 kN/m² D, ху C F 0, =150 kN/m? T = 40 kN/m? 22° ху E A В Fig.1. A stressed soil elementarrow_forward
- The soil profile at a site consists of 5 m sand underlain by clay layer. The ground water table is 2 m below the ground surface. Average void ratio of sand is 0.52. Water content of clay is 42% and degree of saturation of sand above water table is 37%.Assume specific gravity of sand and clay is 2.65. 1. Compute the unit weight of clay. a. 19.82 kN/m³ b. 17.47 kN/m³ c. 18.62 kN/m³ d. 16.20 kN/m³ 2. Compute the total pressure 10 m below the ground surface. a. 185.41 kPa b. 160.25 kPa c. 140.53 kPa d. 153.62 kPa 3. Compute the effective pressure 10 m below the ground surface. a. 106.94 kPa b. 96.52 kPa c. 115.62 kPa d. 108.36 kPaarrow_forwardhiarrow_forwardstion 17 | Dry Sand H Groundwater Table Clay Refer to the soil profile shown. Given H1 = 8.93 m., and H2 = 5.32 m. If the ground water table rises by 2.01 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.56, e = 0.65. Properties of clay: Gs = 2.72, e = 0.87. Round off to two decimal places.arrow_forward
- What is the equivalent coefficient of permeability (k) for all soil layers? where equivalent k(2 and 3) = 1.24 k1 and k4 = 4.41 k1 28 8 A K2 ~ K1 K4 K3 N .a k1 2.174 .b k1 1.511 .c k1 2.237 .d k1 28.250 Your answer is incorrect The correct answer is: 1.511 k1 10arrow_forwardGive me complete solutionarrow_forwardQ: For the soil profile shown in figure. Determine: The effective stress (o') at level (A). Soil 1 k = 0.2 cm/sec Y sat = 19 kN/m³ Soil 2 k = 0.4 cm/sec Y sat = 21 kN/m³ Datum D EL + 2.0 m EL 0.0 m EL - 1.0 m EL - 4.0 m EL - 10.0 marrow_forward
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