Sunlight passing through a pinhole in a piece of paper casts an image of the Sun, as shown. The image size depends on the distance from the pinhole to the floor. If the paper with the pinhole is held about 100 cm above the floor, the diameter of the solar image is about 1 cm. A 1-cm-diamieters coin will just fit over the image (making it easy to measure!). That means about 100 end-to-end coins would fit between the floor and the pinhole. What does this tell you about how many Suns would fit between Earth and the Sun?
Sunlight passing through a pinhole in a piece of paper casts an image of the Sun, as shown. The image size depends on the distance from the pinhole to the floor. If the paper with the pinhole is held about 100 cm above the floor, the diameter of the solar image is about 1 cm. A 1-cm-diamieters coin will just fit over the image (making it easy to measure!). That means about 100 end-to-end coins would fit between the floor and the pinhole. What does this tell you about how many Suns would fit between Earth and the Sun?
Sunlight passing through a pinhole in a piece of paper casts an image of the Sun, as shown. The image size depends on the distance from the pinhole to the floor. If the paper with the pinhole is held about 100 cm above the floor, the diameter of the solar image is about 1 cm. A 1-cm-diamieters coin will just fit over the image (making it easy to measure!). That means about 100 end-to-end coins would fit between the floor and the pinhole. What does this tell you about how many Suns would fit between Earth and the Sun?
A small light source located 1 mm in front of a 1-m2m2 opening illuminates a wall behind. If the wall is 1 mm behind the opening (2 mm from the light source), the illuminated area covers 4 m2m2. How many square meters are illuminated if the wall is 3 mm from the light source? 5 mm? 10 mm?
In the Snellen visual acuity chart, the letters in the 20/40 line subtend an angle of 3 milliradians with respect to the eye when viewed at a distance of 6 meters ( i.e., approximately 20 feet ). Using the small-angle approximation, calculate the actual height of the 20/40 letter, in units of mm?
The diameter of our disk-shaped galaxy, the Milky Way, is about 1.0×105light-years. The distance to the Andromeda galaxy, which is the spiral galaxynearest to the Milky Way, is about 2.5 million light-years. If a scale modelrepresents the Milky Way and Andromeda galaxies as dinner plates 20 cm indiameter, determine the distance between the centers of the two plates.
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