a) Interpretation: The product(s) formed when the alkene shown reacts with NBS is/are to be given. Concept introduction: NBS is used mainly for allylic bromination. An unsymmetrical alkene will lead to a mixture of products as different allyl radicals will be produced as a result of delocalization. The products are not formed in equal amounts because the intermediate allylic radicals are not symmetrical and the reaction at two ends will not take place to the same extent. Reaction at less hindered primary side is more favored. To give: The product(s) formed when the alkene shown is treated with NBS.

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achieve.macmillanlearning.com Canvas EA eac h Hulu YouTube G 3 methyl cyclobutanol - Google Search Ranking Phenol Acidity Course -236 - Organic Chemistry - Mac... ← Assessment Completed 10 of 22 Questions 1 + Netflix paramount plus chem hw Galdehyde reaction with grignard reagent... b My Questions | bartleby M Inbox - chenteislegit@gmail.com - Gmail Due: Fri, Jan 31 Resources Solution Penalized ? Hint Submit Answer Use retrosynthetic analysis to suggest two paths to synthesize 2-methyl-3-hexanol using the Grignard reaction. (Click and drag the appropriate image to the correct position in the reactions.) Route 1 Aldehyde 1 or +98 Aldehyde 2 Route 2 Q6 +100 Solved in 1 attempt Q7 +95 Solved in 2 attempts Q8 +98 Unlimited attempts possible + + Grignard 1 OH H3O+ Grignard 2 Answer Bank Q9 +90 MgBr Unlimited attempts possible CH3CH2CH2MgBr Q10 Unlimited attempts Q11 ? ? +100 in 1 attempt 2-methyl-3-hexanol CH3CH2MgBr H H о H Attempt 3

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Chapter 10.SE, Problem 15VC

Interpretation Introduction

a)

Interpretation:

The product(s) formed when the alkene shown reacts with NBS is/are to be given.

Concept introduction:

NBS is used mainly for allylic bromination. An unsymmetrical alkene will lead to a mixture of products as different allyl radicals will be produced as a result of delocalization. The products are not formed in equal amounts because the intermediate allylic radicals are not symmetrical and the reaction at two ends will not take place to the same extent. Reaction at less hindered primary side is more favored.

To give:

The product(s) formed when the alkene shown is treated with NBS.

Interpretation Introduction

b)

Interpretation:

The product(s) formed when the alkene shown reacts with NBS is/are to be given.

Concept introduction:

NBS is used mainly for allylic bromination. An unsymmetrical alkene will lead to a mixture of products as different allyl radicals will be produced as a result of delocalization. The products are not formed in equal amounts because the intermediate allylic radicals are not symmetrical and the reaction at two ends will not take place to the same extent. Reaction at less hindered primary side is more favored.

To give:

The product(s) formed when the alkene shown is treated with NBS.

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achieve.macmillanlearning.com Canvas EA eac h Hulu YouTube G 3 methyl cyclobutanol - Google Search Ranking Phenol Acidity Course -236 - Organic Chemistry - Mac... ← Assessment Completed 10 of 22 Questions 1 + Netflix paramount plus chem hw Galdehyde reaction with grignard reagent... b My Questions | bartleby M Inbox - chenteislegit@gmail.com - Gmail Due: Fri, Jan 31 Resources Solution Penalized ? Hint Submit Answer Use retrosynthetic analysis to suggest two paths to synthesize 2-methyl-3-hexanol using the Grignard reaction. (Click and drag the appropriate image to the correct position in the reactions.) Route 1 Aldehyde 1 or +98 Aldehyde 2 Route 2 Q6 +100 Solved in 1 attempt Q7 +95 Solved in 2 attempts Q8 +98 Unlimited attempts possible + + Grignard 1 OH H3O+ Grignard 2 Answer Bank Q9 +90 MgBr Unlimited attempts possible CH3CH2CH2MgBr Q10 Unlimited attempts Q11 ? ? +100 in 1 attempt 2-methyl-3-hexanol CH3CH2MgBr H H о H Attempt 3

2) (4 pt) After the reaction was completed, the student collected the following data. Crude product data is the data collected after the reaction is finished, but before the product is purified. "Pure" product data is the data collected after attempted purification using recrystallization. Student B's data: Crude product data "Pure" product data after recrystallization Crude mass: 0.93 g grey solid Crude mp: 96-106 °C Crude % yield: Pure mass: 0.39 g white solid Pure mp: 111-113 °C Pure % yield: a) Calculate the crude and pure percent yields for the student's reaction. b) Summarize what is indicated by the crude and pure melting points.

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