EP BASIC CHEMISTRY-STANDALONE ACCESS
EP BASIC CHEMISTRY-STANDALONE ACCESS
6th Edition
ISBN: 9780134999890
Author: Timberlake
Publisher: PEARSON CO
Question
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Chapter 10.7, Problem 56PP

(a)

Interpretation Introduction

Interpretation:

Interpret the electronegativity difference for O-H and determine whether the bond is non polar, polar or ionic.

Concept Introduction:

The large difference in the electronegativity between the atoms of the molecule results in polar nature of the molecule.

If the difference in electronegativity is lower or approaching to 0 then the molecule will have non polar nature.

The range of non-polar bond is 0 to 0.4 while for polar covalent bond the range is 0.4 to 1.8 and for ionic bond the range is 1.8 to 3.3.

(b)

Interpretation Introduction

Interpretation:

Interpret the electronegativity difference for Na-O and determine whether the bond is non polar, polar or ionic.

Concept Introduction:

The large difference in the electronegativity between the atoms of the molecule results in polar nature of the molecule.

If the difference in electronegativity is lower or approaching to 0 then the molecule will have non polar nature.

The range of non-polar bond is 0 to 0.4 while for polar covalent bond the range is 0.4 to 1.8 and for ionic bond the range is 1.8 to 3.3.

(c)

Interpretation Introduction

Interpretation:

Interpret the electronegativity difference for C-Br and determine whether the bond is non polar, polar or ionic.

Concept Introduction:

The large difference in the electronegativity between the atoms of the molecule results in polar nature of the molecule.

If the difference in electronegativity is lower or approaching to 0 then the molecule will have non polar nature.

The range of non-polar bond is 0 to 0.4 while for polar covalent bond the range is 0.4 to 1.8 and for ionic bond the range is 1.8 to 3.3.

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Chapter 10 Solutions

EP BASIC CHEMISTRY-STANDALONE ACCESS

Ch. 10.2 - Draw two resonance structures for each of the...Ch. 10.2 - Draw two resonance structures for each of the...Ch. 10.3 - Prob. 13PPCh. 10.3 - Choose the shape (1 to 6) that matches each of the...Ch. 10.3 - Prob. 15PPCh. 10.3 - Prob. 16PPCh. 10.3 - Prob. 17PPCh. 10.3 - Prob. 18PPCh. 10.3 - Use VSEPR theory to predict the shape of each of...Ch. 10.3 - Prob. 20PPCh. 10.3 - Prob. 21PPCh. 10.3 - Draw the Lewis structure and predict the shape for...Ch. 10.4 - Describe the trend in electronegativity as...Ch. 10.4 - Describe the trend in electronegativity as...Ch. 10.4 - Prob. 25PPCh. 10.4 - Which electronegativity difference (a, b, or c)...Ch. 10.4 - Using the periodic table, arrange the atoms in...Ch. 10.4 - Using the periodic table, arrange the atoms in...Ch. 10.4 - Predict whether the bond between each of the...Ch. 10.4 - Predict whether the bond between each of the...Ch. 10.4 - For the bond between each of the following pairs...Ch. 10.4 - For the bond between each of the following pairs...Ch. 10.5 - Why is F2 a nonpolar molecule, but HF is a polar...Ch. 10.5 - Why is CCl4 a nonpolar molecule, but PCl3 is a...Ch. 10.5 - Identify each of the following molecules as polar...Ch. 10.5 - Identify each of the following molecules as polar...Ch. 10.5 - Prob. 37PPCh. 10.5 - Prob. 38PPCh. 10.6 - Prob. 39PPCh. 10.6 - Prob. 40PPCh. 10.6 - Identify the strongest intermolecular forces...Ch. 10.6 - Identify the strongest intermolecular forces...Ch. 10.6 - Prob. 43PPCh. 10.6 - Prob. 44PPCh. 10.7 - Using Figure 10.6, calculate the heat change...Ch. 10.7 - Using Figure 10.6, calculate the heat change...Ch. 10.7 - Prob. 47PPCh. 10.7 - Using Figure 10.6, calculate the heat change...Ch. 10.7 - Using Figure 10.6 and the specific heat of water,...Ch. 10.7 - Using Figure 10.6 and the specific heat of water,...Ch. 10.7 - An ice bag containing 275 g of ice at 0 °C was...Ch. 10.7 - Prob. 52PPCh. 10.7 - Prob. 53PPCh. 10.7 - In the preparation of liquid nitrogen, how many...Ch. 10.7 - Using the electronegativity values in Figure 10.2,...Ch. 10.7 - Prob. 56PPCh. 10.7 - Prob. 57PPCh. 10.7 - a. Draw two resonance structures for bicarbonate...Ch. 10 - State the number of valence electrons, bonding...Ch. 10 - State the number of valence electrons, bonding...Ch. 10 - Prob. 61UTCCh. 10 - Prob. 62UTCCh. 10 - Consider the following bonds: Ca and O, C and O, K...Ch. 10 - Consider the following bonds: F and Cl, Cl and Cl,...Ch. 10 - Identify the major intermolecular forces between...Ch. 10 - Prob. 66UTCCh. 10 - Prob. 67UTCCh. 10 - Prob. 68UTCCh. 10 - Prob. 69UTCCh. 10 - Prob. 70UTCCh. 10 - Prob. 71UTCCh. 10 - Prob. 72UTCCh. 10 - Prob. 73APPCh. 10 - Determine the total number of valence electrons in...Ch. 10 - Draw the Lewis structures for each of the...Ch. 10 - Draw the Lewis structures for each of the...Ch. 10 - Draw resonance structures for each of the...Ch. 10 - Prob. 78APPCh. 10 - Use the periodic table to arrange the following...Ch. 10 - Use the periodic table to arrange the following...Ch. 10 - Select the more polar bond in each of the...Ch. 10 - Select the more polar bond in each of the...Ch. 10 - Show the dipole arrow for each of the following...Ch. 10 - Show the dipole arrow for each of the following...Ch. 10 - Calculate the electronegativity difference and...Ch. 10 - Calculate the electronegativity difference and...Ch. 10 - Prob. 87APPCh. 10 - For each of the following, draw the Lewis...Ch. 10 - For each of the following, draw the Lewis...Ch. 10 - For each of the following, draw the Lewis...Ch. 10 - Prob. 91APPCh. 10 - Predict the shape and polarity of each of the...Ch. 10 - Prob. 93APPCh. 10 - Prob. 94APPCh. 10 - Prob. 95APPCh. 10 - Indicate the major type of intermolecular...Ch. 10 - When it rains or snows, the air temperature seems...Ch. 10 - Prob. 98APPCh. 10 - Using Figure 10.6, calculate the grams of ice that...Ch. 10 - Using Figure 10.6, calculate the grams of ethanol...Ch. 10 - Prob. 101APPCh. 10 - Using Figure 10.6, calculate the grams of benzene...Ch. 10 - Prob. 103CPCh. 10 - Prob. 104CPCh. 10 - Prob. 105CPCh. 10 - Prob. 106CPCh. 10 - Prob. 107CPCh. 10 - The melting point of benzene is 5.5 °C, and its...Ch. 10 - A 45.0-g piece of ice at 0.0 °C is added to a...Ch. 10 - An ice cube at 0 °C with a mass of 115 g is added...Ch. 10 - Prob. 111CPCh. 10 - Prob. 112CPCh. 10 - Prob. 13CICh. 10 - Prob. 14CICh. 10 - Prob. 15CICh. 10 - Ethanol, C2H6O , is obtained from renewable crops...Ch. 10 - Chloral hydrate, a sedative and hypnotic, was the...Ch. 10 - Ethylene glycol, C2H6O2 , used as a coolant and...Ch. 10 - Prob. 19CICh. 10 - Prob. 20CI
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