
Concept explainers
(a)
Interpretation:
Interpret total number of valence electrons in H-NO2.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
(b)
Interpretation:
Interpret total number of valence electron in CH3CHO.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
(c)
Interpretation:
Interpret total number of valence electron in PH4+ .
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
(d)
Interpretation:
Interpret total number of valence electron in SO32-.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with other atom.
The bonds formed between two atoms by sharing of electrons are known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron for a molecule can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule such as:
For HxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)

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Chapter 10 Solutions
EP BASIC CHEMISTRY-STANDALONE ACCESS
- This molecule undergoes an E1 mechanism when stirred in methanol. 3rd attempt CH₂OH CH₂OH 6148 O See Periodic Table. See Hint Draw 3 chemical species including formal charges and lone pairs of electrons. Add the missing curved arrow notation. H N O O SA 3 Br Iarrow_forwardComplete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 1st attempt Y 0 + Provide the missing curved arrow notation. 01: See Periodic Table See Hint H C Br Iarrow_forwardPlease help answer number 2. Thanks in advance.arrow_forward
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- Please help with number 6 I got a negative number could that be right?arrow_forward1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.arrow_forwardGive the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.arrow_forward
- Five isomeric alkenes. A through each undergo catalytic hydrogenation to give 2-methylpentane The IR spectra of these five alkenes have the key absorptions (in cm Compound Compound A –912. (§), 994 (5), 1643 (%), 3077 (1) Compound B 833 (3), 1667 (W), 3050 (weak shoulder on C-Habsorption) Compound C Compound D) –714 (5), 1665 (w), 3010 (m) 885 (3), 1650 (m), 3086 (m) 967 (5), no aharption 1600 to 1700, 3040 (m) Compound K Match each compound to the data presented. Compound A Compound B Compound C Compound D Compoundarrow_forward7. The three sets of replicate results below were accumulated for the analysis of the same sample. Pool these data to obtain the most efficient estimate of the mean analyte content and the standard deviation. Lead content/ppm: Set 1 Set 2 Set 3 1. 9.76 9.87 9.85 2. 9.42 9.64 9.91 3. 9.53 9.71 9.42 9.81 9.49arrow_forwardDraw the Zaitsev product famed when 2,3-dimethylpentan-3-of undergoes an El dehydration. CH₂ E1 OH H₁PO₁ Select Draw Templates More QQQ +H₂Oarrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning
