Concept explainers
(a)
Interpretation: We need to identify GeH4 as polar or non-polar molecule.
Concept Introduction : The
(b)
Interpretation: We need to identify I2 as polar or non-polar molecule.
Concept Introduction : The chemical bonds can be classified as ionic bond and covalent bonds. Ionic bonds are formed between cation and anion. Here both of these are charged ions. On the contrary, covalent bond is formed by equal sharing of electrons. Further covalent bond can be classified as polar and non-polar covalent bond.
(c)
Interpretation: We need to identify CF3Cl as polar or non-polar molecule.
Concept Introduction : The chemical bonds can be classified as ionic bond and covalent bonds. Ionic bonds are formed between cation and anion. Here both of these are charged ions. On the contrary, covalent bond is formed by equal sharing of electrons. Further covalent bond can be classified as polar and non-polar covalent bond.
(d)
Interpretation: We need to identify PCl3 as polar or non-polar molecule.
Concept Introduction : The chemical bonds can be classified as ionic bond and covalent bonds. Ionic bonds are formed between cation and anion. Here both of these are charged ions. On the contrary, covalent bond is formed by equal sharing of electrons. Further covalent bond can be classified as polar and non-polar covalent bond.
(e)
Interpretation: We need to identify BCl3 as polar or non-polar molecule.
Concept Introduction : The chemical bonds can be classified as ionic bond and covalent bonds. Ionic bonds are formed between cation and anion. Here both of these are charged ions. On the contrary, covalent bond is formed by equal sharing of electrons. Further covalent bond can be classified as polar and non-polar covalent bond.
(f)
Interpretation: We need to identify SCl2 as polar or non-polar molecule.
Concept Introduction : The chemical bonds can be classified as ionic bond and covalent bonds. Ionic bonds are formed between cation and anion. Here both of these are charged ions. On the contrary, covalent bond is formed by equal sharing of electrons. Further covalent bond can be classified as polar and non-polar covalent bond.
Want to see the full answer?
Check out a sample textbook solutionChapter 10 Solutions
EP BASIC CHEMISTRY-STANDALONE ACCESS
- Please correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forwardFor each molecule below, predict whether the molecule would be expected to show aromatic character or not. Explain your answer in each case. These molecule are planner. [THREE] a. b. HIN: (14) annulene C. OH d. :0: :0: +arrow_forward
- Drawing Instructions: Draw structures corresponding to each of the given names. a. Draw: 2-ethyl-1,3-butadiene b. Name:arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardс. d. СнЗ Сизена=-4=4 Cla H Eget3 над f. e. H-C=C-CH3 + 285 → H-C=C-CH3+2не H-C=C-CH3 + Nanta» g+ CH₂ CH₂-G = G-C₁₂-G=CH₂ + 2HI→ H H H ALarrow_forward
- The IR (infrared) spectra of two pure compounds (0.010 M compound A in solvent and 0.010 M compound B in solvent) are given. The pathlength of the cell is 1.00 cm. The y-axis in the spectra is transmittance rather than absorption, so that the wavenumbers at which there is a dip in the curve correspond to absorption peaks. A mixture of A and B in unknown concentrations gave a percent transmittance of 49.8% at 2976 cm¹ and 44.9% at 3030 cm-1 Wavenumber 0.010 M A 0.010 M B Unknown 3030 cm-1 35.0% 93.0% 44.9% 2976 cm-¹ 76.0% 42.0% 49.8% What are the concentrations of A and B in the unknown sample? Transmittance (%) 100 90 80 70 60 50 40 2976 cm-1 30 3030 cm-1 20 Pure A 10 Pure B 0 3040 2990 Wavenumber (cm-1) 2940 2890arrow_forwardsynthesize 1-propyne starting with propane.arrow_forwardstarting reactant IV target + enantiomer 1) BH3, THF 2) H₂O2, NaOH, H₂O 1) Hg(OAc)2, THF, H₂O (or ROH) 2) NaBH4 D2, Pt/C H₂, Pt/C D2, Lindlar catalyst or Ni₂B H₂, Lindlar catalyst or Ni₂B NaNH, OH/H₂O or SH/H₂S H₂O/H₂O 1) 03 2) H₂O 1) 03 2) (CH3)2S HBr, w/ROOR HBr, (cold, dark, no ROOR) Naº, NH3(e) NBS (trace Br2), light HgSO4, H2SO4, H₂O Naº, ROH 1) Sia₂BH, THF 2) H2O2, NaOH, H₂O H3O/ROH or H₂O*/RSH OR/ROH or SR/RSH 1) OsO4, NMO 2) NaHSO3, H₂O 1) MCPBA (peroxy acid) 2) H3O, H2O (or ROH or RSH) KMnO4 (warm, concentrated) Br₂/H₂O Br₂, heat or light Br2, cold, dark, no peroxides (CH3)3CO(CH3)3COH ROH or RSH H₂O KMnO4/OH (cold, dilute)arrow_forward
- Nonearrow_forwardIndicate whether the ability of atoms to associate with each other depends on electron affinity.arrow_forward1) Write the reduction half reactions and find the reduction potential for each pair.a. Zn/Zn2+b. Cu/Cu2+c. Al/Al3+d. Ag/Ag1+ 2) For each of the following voltaic cells, identify the anode, cathode, write the standard cell notation/diagram, and predict the cell potential.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning