EBK ESSENTIAL ORGANIC CHEMISTRY
EBK ESSENTIAL ORGANIC CHEMISTRY
3rd Edition
ISBN: 8220100659461
Author: Bruice
Publisher: PEARSON
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Chapter 10.3, Problem 7P
Interpretation Introduction

Interpretation:

The hydrocarbon from the given m/z values has to be identified.

Concept introduction:

Interpreting a mass spectrum:

  1. 1. The each m/z values is the m/z value of one the fragments to the nearest whole number.
  2. 2. The peak with the highest m/z value in the molecular ions (M+), the fragment that results when the molecules lose electrons as result of being bombarding by the electron beam.
  3. 3. The m/z value of the molecular ion gives the molecular mass of the compound.
  4. 4. Peaks with smaller m/z values, fragment ion peak represent positively charged fragments of the molecular ion.

Base peak of mass spectrum:  The base peak is the one of highest (or) tallest peak, it has great abundance.  It has the greatest relative abundance because it is generally the most stable positively charged fragment.

Percentage of base peak:  The base peak is assigned a relative abundance (RA) of 100% and the relative abundance of each other peaks is respective mass spectrum percentage of base peak.  For example the weak bonds break in preference to strong bonds and bonds that break to form more stable fragments break in performance to those that form less stable fragments.

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Chapter 10 Solutions

EBK ESSENTIAL ORGANIC CHEMISTRY

Ch. 10.6 - Identify the ketone responsible for the mass...Ch. 10.6 - Prob. 13PCh. 10.8 - Prob. 14PCh. 10.8 - Prob. 15PCh. 10.12 - Which will occur at a larger wavenumber: a. a C :...Ch. 10.13 - Which will occur at a larger wavenumber: a. the C...Ch. 10.13 - Prob. 18PCh. 10.13 - Prob. 19PCh. 10.13 - Which will show an O 8 H stretch at a larger...Ch. 10.14 - Prob. 21PCh. 10.14 - Prob. 22PCh. 10.15 - Prob. 23PCh. 10.15 - Prob. 24PCh. 10.17 - Prob. 25PCh. 10.18 - Prob. 26PCh. 10.18 - Prob. 27PCh. 10.19 - Prob. 28PCh. 10.19 - Prob. 29PCh. 10.22 - How many signals would you expect to see in the 1H...Ch. 10.22 - Prob. 31PCh. 10.22 - Prob. 32PCh. 10.23 - Where would you expect to find the 1H NMR signal...Ch. 10.24 - Prob. 34PCh. 10.25 - Prob. 35PCh. 10.25 - Prob. 36PCh. 10.25 - Prob. 37PCh. 10.26 - Prob. 38PCh. 10.26 - Which of the following compounds is responsible...Ch. 10.27 - Prob. 40PCh. 10.27 - Prob. 41PCh. 10.27 - The 1H NMR spectra of two carboxylic acids with...Ch. 10.28 - Prob. 43PCh. 10.28 - Prob. 44PCh. 10.28 - Prob. 45PCh. 10.28 - Describe the 1H NMR spectrum you would expect for...Ch. 10.28 - Identify the compound with molecular formula...Ch. 10.29 - Prob. 48PCh. 10.29 - Prob. 49PCh. 10.29 - Identify the compound with a molecular formula of...Ch. 10 - In the mass spectrum of the following compounds,...Ch. 10 - For each of the following pairs of compounds,...Ch. 10 - Draw the structure of a saturated hydrocarbon that...Ch. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - How could you use UV spectroscopy to distinguish...Ch. 10 - Prob. 57PCh. 10 - Predict the relative intensities of the molecular...Ch. 10 - Prob. 59PCh. 10 - List the following compounds in order from highest...Ch. 10 - How can 1H NMR be used to prove that the addition...Ch. 10 - There are four esters with molecular formula...Ch. 10 - Prob. 63PCh. 10 - Prob. 64PCh. 10 - Each of the IR spectra presented here is...Ch. 10 - Prob. 66PCh. 10 - Five compounds are shown for each of the following...Ch. 10 - Prob. 68PCh. 10 - Prob. 69PCh. 10 - Phenolphthalein is an acidbase indicator. In...Ch. 10 - Which one of the following five compounds produced...Ch. 10 - Prob. 72PCh. 10 - Prob. 73PCh. 10 - Prob. 74PCh. 10 - How could 1H NMR distinguish between the compounds...Ch. 10 - Prob. 76PCh. 10 - Prob. 77PCh. 10 - The 1H NMR spectra of three isomers with molecular...Ch. 10 - The 1H NMR spectra of three isomers with molecular...Ch. 10 - Identify the following compounds. (Relative...Ch. 10 - An alkyl halide reacts with an alkoxide ion to...Ch. 10 - Determine the structure of a compound with...
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Mass Spectrometry; Author: Professor Dave Explains;https://www.youtube.com/watch?v=hSirWciIvSg;License: Standard YouTube License, CC-BY