Concept explainers
Interpretation:
Compound A and B has to be identified using the given
Concept introduction:
The signal in the spectrum of a compound is proportional to the number of carbons that are present in the different environment within the molecule. The carbon which is present in the electron-rich environment shows a signal at a lower frequency and vice-versa. Therefore, the carbon that is present nearest to the electron-withdrawing groups produces a high-frequency signal.
The
The coupling between the carbon and the protons attached to it is called heteronuclear coupling.
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EBK ESSENTIAL ORGANIC CHEMISTRY
- Compound A has molecular formula C5H10O. It shows three signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.1 ppm, a singlet of integral 3 at 2.14 ppm, and a quintet of integral 1 at 2.58 ppm. Suggest a structure for A and explain your reasoning.arrow_forwardCompound A exhibits two signals in its 'H NMR spectrum at 2.64 and 3.69 ppm and the ratio of the absorbing signals is 2:3. Compound B exhibits two signals in its 'H NMR spectrum at 2.09 and 4.27 ppm and the ratio of the absorbing signals is 3:2. Which compound corresponds to CH;O,CCH,CH2CO,CH3 (dimethyl succinate) and which compound corresponds to CH;CO,CH2CH,O,CCH; (ethylene diacetate)?arrow_forwardCompound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forward
- The 1H-NMR spectrum of Compound C shows five signals – δ 2.38 (1H, dt), 2.72 (1H, dt), 5.34 (1H, t), 5.49 (2H, ddd), 6.27 (2H, dd) ppm. Its 13C-NMR spectrum has four signals – δ 26, 58, 127, 129 ppm. In the compound’s mass spectrum, the M+1 peak appears at m/z = 115. An M+2 peak, whose intensity is roughly one-third that of the M+1 peak, also appears. Suggest a structure for this compound.arrow_forward1Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3Hdoublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identifycompounds A and B.arrow_forward
- Compound b is a derivative of compound a. Comparing ¹H NMR of a and b, we found that two signals shown in compound a move to downfield around 7.38 ppm and 8.42 ppm in compound b. Identify the two protons that most likely give rise to these signals and justify your decision. (3 pts) (a) Ĵ (b)arrow_forwardCompound 1 has molecular formula C7H15Cl. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Propose structures for compound 1, explaining how you reach your conclusion.arrow_forwardA compound with molecular formula C3H8O produces a broad signal between 3200 and 3600 cm1 in its IR spectrum and produces two signals in its 1°C NMR spectrum. Draw the structure of the compound.arrow_forward
- A compound has a formula of C19H16- Five signals appear in its 1°C NMR spectrum-one at 57 ppm and the remaining four between 126 and 144 ppm. In its 'H NMR spectrum, an unresolved multiplet (15 H) appears between 6.9 and 7.44 ppm and a singlet (1 H) appears at 5.5 ppm. What is the structure of this compound?arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forwardDraw the structure of a compound with the molecular formula C8H₁0 that exhibits five signals in its ¹3C NMR spectrum, four of which appear between 100 and 150 ppm.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning