![McDougal Littell Jurgensen Geometry: Student Edition Geometry](https://www.bartleby.com/isbn_cover_images/9780395977279/9780395977279_largeCoverImage.gif)
a.
To use a piece of cardboard to study center of mass.
a.
![Check Mark](/static/check-mark.png)
Explanation of Solution
Given:
A piece of cardboard in the shape of a scalene
Cut three holes, one each near the vertex.
Use a thread to join all the three holes and leave one thread hanging with a knob attached.
Now try to balance the triangle on the knob.
The triangle will stay still on the knob only when the triangle is placed on its center of mass.
Conclusion:
Therefore, the triangle can balance on the center of mass.
b.
To explain why in geometry the point of intersection of intersection of the medians of a triangle is called the centroid of the triangle.
b.
![Check Mark](/static/check-mark.png)
Explanation of Solution
Given:
A scalene triangle
A median of a triangle is a line joining from a vertex of triangle to the midpoint of the opposite side. The median will bisect the opposite side.
The intersection of medians of a triangle is known as centroid of the triangle.
The centroid of the triangle is also known as center of gravity of the triangle. This means that a triangular cardboard can be balanced on one figure if the finger is placed on the center of gravity.
The centroid represents the center of the given triangle.
Conclusion:
Hence, the point of intersection of medians is known as centroid.
Chapter 10 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
Additional Math Textbook Solutions
University Calculus: Early Transcendentals (4th Edition)
Basic Business Statistics, Student Value Edition
Calculus: Early Transcendentals (2nd Edition)
Thinking Mathematically (6th Edition)
College Algebra with Modeling & Visualization (5th Edition)
Elementary Statistics (13th Edition)
- Question 1 Calculate the Moment about the point A in Nx m A 300 N 2 m 500 N 4 B C 0.8 m 1.2 marrow_forwardWhat is the area of this figure? 22 mm 5 mm 3 mm 3 mm 7 mm 4 mm Write your answer using decimals. Use 3.14 for л. Submit square millimetersarrow_forwardThis figure is made up of a rectangle and parallelogram. What is the area of this figure? Enter your answer in the box. Do not round any side lengths.arrow_forward
- Rhombus PQRSPQRS is shown on the coordinate plane. Points MM and NN are midpoints of their respective sides.arrow_forwardPlease help me answer this question!. Please handwrite it. I don't require AI answers. Thanks for your time!.arrow_forward1 What is the area of triangle ABC? 12 60° 60° A D B A 6√√3 square units B 18√3 square units 36√3 square units D 72√3 square unitsarrow_forward
- ◆ Switch To Light Mode HOMEWORK: 18, 19, 24, 27, 29 ***Please refer to the HOMEWORK sheet from Thursday, 9/14, for the problems ****Please text or email me if you have any questions 18. Figure 5-35 is a map of downtown Royalton, showing the Royalton River running through the downtown area and the three islands (A, B, and C) connected to each other and both banks by eight bridges. The Down- town Athletic Club wants to design the route for a marathon through the downtown area. Draw a graph that models the layout of Royalton. FIGURE 5-35 North Royalton Royalton River South Royption 19. A night watchman must walk the streets of the Green Hills subdivision shown in Fig. 5-36. The night watch- man needs to walk only once along each block. Draw a graph that models this situation.arrow_forwardSolve this question and check if my answer provided is correctarrow_forwardProof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.arrow_forward
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337614085/9781337614085_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285195698/9781285195698_smallCoverImage.gif)