Chapter 10.2, Problem 62ES

A polar graph of $r=f\left(\theta \right)$ is given over the stated interval. Sketch the graph of

$\begin{array}{l}\left(\text{a}\right)r=f\left(-\theta \right)\\ \left(\text{b}\right)r=f\left(\theta -\frac{\pi }{2}\right)\\ \left(\text{c}\right)r=f\left(\theta +\frac{\pi }{2}\right)\\ \left(\text{d}\right)r=-f\left(\theta \right).\end{array}$

$\pi /2\le \theta \le \pi$