Pre-Algebra
1st Edition
ISBN: 9780618800766
Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold
Publisher: Houghton Mifflin-High School
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 10.1, Problem 23E
(a)
To determine
To find: The scale of drawing of the surface of the smallest table.
(a)
Expert Solution
Answer to Problem 23E
1:24
Explanation of Solution
Given: A set of nested tables. The surface of the tables will be
Each of the two congruent edges of the surface of the smallest table has a length of 24 inches.
First draw smallest triangle.
Let the scale of congruent side be 1:24.
1 unit = 24 in
So, scale drawing would be
(b)
To determine
To find:The length of two congruent edges of the surface of the largest triangle.
(b)
Expert Solution
Answer to Problem 23E
Explanation of Solution
Given: A set of nested tables. The surface of the tables will be
The ratio of an edge length of the surface of the smallest table to a corresponding edge of the largest table is 1:2.
The length of congruent edges of the surface of the smallest table is 24 in.
The ratio of an edge length of the surface of the smallest table to a corresponding edge of the largest table is 1:2.
Let the length of the surface of the largest table be x in.
So, the ratio is 24: x which is equal to 1:2
Therefore,
(C)
To determine
To find: The length of two congruent edges of the surface of the middle sized table.
(C)
Expert Solution
Answer to Problem 23E
Explanation of Solution
Given: A set of nested tables. The surface of the tables will be
The ratio of an edge length of the surface of the middle sized table to smallest table is 3:2.
The length of congruent edges of the surface of the smallest table is 24 in.
The ratio of an edge length of the surface of the middle sized table to smallest table is 3:2.
Let the length of edge of the surface of themiddle sized table be x in.
So, the ratio is x :24 which is equal to 3:2
Therefore,
(d)
To determine
To find: The length of thirdedge of the surface of the each table.
(d)
Expert Solution
Answer to Problem 23E
Smallest table = 34 in
Middle size table = 51 in
Largest table = 68 in
Explanation of Solution
Given: A set of nested tables. The surface of the tables will be
The scale of the each table.
So, the ratio of the congruent sides and third side is
For smallest table, length of third side x,
For middle sized table, length of third side y ,
For largest table, length of third side z ,
Chapter 10 Solutions
Pre-Algebra
Ch. 10.1 - Prob. 1CCh. 10.1 - Prob. 2CCh. 10.1 - Prob. 3CCh. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7E
Ch. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10ECh. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.1 - Prob. 32ECh. 10.2 - Prob. 1CCh. 10.2 - Prob. 2CCh. 10.2 - Prob. 3CCh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.3 - Prob. 1CCh. 10.3 - Prob. 2CCh. 10.3 - Prob. 3CCh. 10.3 - Prob. 4CCh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Prob. 24ECh. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - Prob. 28ECh. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - Prob. 31ECh. 10.3 - Prob. 32ECh. 10.3 - Prob. 33ECh. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 41ECh. 10.3 - Prob. 42ECh. 10.3 - Prob. 43ECh. 10.4 - Prob. 1CCh. 10.4 - Prob. 2CCh. 10.4 - Prob. 3CCh. 10.4 - Prob. 4CCh. 10.4 - Prob. 5CCh. 10.4 - Prob. 6CCh. 10.4 - Prob. 7CCh. 10.4 - Prob. 8CCh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - Prob. 16ECh. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.4 - Prob. 29ECh. 10.4 - Prob. 30ECh. 10.4 - Prob. 31ECh. 10.4 - Prob. 32ECh. 10.4 - Prob. 33ECh. 10.4 - Prob. 34ECh. 10.4 - Prob. 35ECh. 10.4 - Prob. 36ECh. 10.4 - Prob. 37ECh. 10.4 - Prob. 38ECh. 10.4 - Prob. 39ECh. 10.4 - Prob. 40ECh. 10.4 - Prob. 41ECh. 10.4 - Prob. 42ECh. 10.4 - Prob. 43ECh. 10.4 - Prob. 44ECh. 10.4 - Prob. 45ECh. 10.5 - Prob. 1CCh. 10.5 - Prob. 2CCh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.5 - Prob. 8ECh. 10.5 - Prob. 9ECh. 10.5 - Prob. 10ECh. 10.5 - Prob. 11ECh. 10.5 - Prob. 12ECh. 10.5 - Prob. 13ECh. 10.5 - Prob. 14ECh. 10.5 - Prob. 15ECh. 10.5 - Prob. 16ECh. 10.5 - Prob. 17ECh. 10.5 - Prob. 19ECh. 10.5 - Prob. 20ECh. 10.5 - Prob. 21ECh. 10.5 - Prob. 22ECh. 10.5 - Prob. 23ECh. 10.5 - Prob. 24ECh. 10.5 - Prob. 25ECh. 10.5 - Prob. 26ECh. 10.5 - Prob. 27ECh. 10.5 - Prob. 28ECh. 10.5 - Prob. 29ECh. 10.5 - Prob. 30ECh. 10.5 - Prob. 31ECh. 10.6 - Prob. 1CCh. 10.6 - Prob. 2CCh. 10.6 - Prob. 1ECh. 10.6 - Prob. 2ECh. 10.6 - Prob. 3ECh. 10.6 - Prob. 4ECh. 10.6 - Prob. 5ECh. 10.6 - Prob. 6ECh. 10.6 - Prob. 7ECh. 10.6 - Prob. 8ECh. 10.6 - Prob. 9ECh. 10.6 - Prob. 10ECh. 10.6 - Prob. 11ECh. 10.6 - Prob. 12ECh. 10.6 - Prob. 13ECh. 10.6 - Prob. 14ECh. 10.6 - Prob. 15ECh. 10.6 - Prob. 16ECh. 10.6 - Prob. 17ECh. 10.6 - Prob. 18ECh. 10.6 - Prob. 19ECh. 10.6 - Prob. 20ECh. 10.6 - Prob. 21ECh. 10.6 - Prob. 22ECh. 10.6 - Prob. 23ECh. 10.6 - Prob. 24ECh. 10.6 - Prob. 25ECh. 10.6 - Prob. 26ECh. 10.6 - Prob. 27ECh. 10.6 - Prob. 28ECh. 10.6 - Prob. 29ECh. 10.6 - Prob. 31ECh. 10.6 - Prob. 32ECh. 10.6 - Prob. 33ECh. 10.6 - Prob. 34ECh. 10.6 - Prob. 35ECh. 10.6 - Prob. 36ECh. 10.6 - Prob. 37ECh. 10.6 - Prob. 38ECh. 10.6 - Prob. 39ECh. 10.6 - Prob. 40ECh. 10.6 - Prob. 41ECh. 10.7 - Prob. 1CCh. 10.7 - Prob. 2CCh. 10.7 - Prob. 3CCh. 10.7 - Prob. 4CCh. 10.7 - Prob. 1ECh. 10.7 - Prob. 2ECh. 10.7 - Prob. 3ECh. 10.7 - Prob. 4ECh. 10.7 - Prob. 5ECh. 10.7 - Prob. 6ECh. 10.7 - Prob. 7ECh. 10.7 - Prob. 8ECh. 10.7 - Prob. 9ECh. 10.7 - Prob. 10ECh. 10.7 - Prob. 11ECh. 10.7 - Prob. 12ECh. 10.7 - Prob. 13ECh. 10.7 - Prob. 14ECh. 10.7 - Prob. 15ECh. 10.7 - Prob. 16ECh. 10.7 - Prob. 17ECh. 10.7 - Prob. 18ECh. 10.7 - Prob. 19ECh. 10.7 - Prob. 20ECh. 10.7 - Prob. 21ECh. 10.7 - Prob. 22ECh. 10.7 - Prob. 23ECh. 10.7 - Prob. 24ECh. 10.7 - Prob. 25ECh. 10.7 - Prob. 26ECh. 10.7 - Prob. 27ECh. 10.7 - Prob. 28ECh. 10.7 - Prob. 29ECh. 10.7 - Prob. 30ECh. 10.7 - Prob. 31ECh. 10.7 - Prob. 32ECh. 10.8 - Prob. 1CCh. 10.8 - Prob. 2CCh. 10.8 - Prob. 3CCh. 10.8 - Prob. 1ECh. 10.8 - Prob. 2ECh. 10.8 - Prob. 3ECh. 10.8 - Prob. 4ECh. 10.8 - Prob. 5ECh. 10.8 - Prob. 6ECh. 10.8 - Prob. 7ECh. 10.8 - Prob. 8ECh. 10.8 - Prob. 9ECh. 10.8 - Prob. 10ECh. 10.8 - Prob. 11ECh. 10.8 - Prob. 12ECh. 10.8 - Prob. 13ECh. 10.8 - Prob. 14ECh. 10.8 - Prob. 15ECh. 10.8 - Prob. 16ECh. 10.8 - Prob. 17ECh. 10.8 - Prob. 18ECh. 10.8 - Prob. 19ECh. 10.8 - Prob. 20ECh. 10.8 - Prob. 21ECh. 10.8 - Prob. 22ECh. 10.8 - Prob. 23ECh. 10.8 - Prob. 24ECh. 10.8 - Prob. 25ECh. 10.8 - Prob. 26ECh. 10.8 - Prob. 27ECh. 10.8 - Prob. 28ECh. 10.8 - Prob. 29ECh. 10.8 - Prob. 30ECh. 10.8 - Prob. 31ECh. 10.8 - Prob. 32ECh. 10.8 - Prob. 33ECh. 10.8 - Prob. 34ECh. 10 - Prob. 1PSQCh. 10 - Prob. 2PSQCh. 10 - Prob. 3PSQCh. 10 - Prob. 4PSQCh. 10 - Prob. 5PSQCh. 10 - Prob. 6PSQCh. 10 - Prob. 7PSQCh. 10 - Prob. 8PSQCh. 10 - Prob. 9PSQCh. 10 - Prob. 10PSQCh. 10 - Prob. 11PSQCh. 10 - Prob. 1MCQCh. 10 - Prob. 2MCQCh. 10 - Prob. 3MCQCh. 10 - Prob. 4MCQCh. 10 - Prob. 5MCQCh. 10 - Prob. 6MCQCh. 10 - Prob. 7MCQCh. 10 - Prob. 8MCQCh. 10 - Prob. 9MCQCh. 10 - Prob. 10MCQCh. 10 - Prob. 11MCQCh. 10 - Prob. 1CRCh. 10 - Prob. 2CRCh. 10 - Prob. 3CRCh. 10 - Prob. 4CRCh. 10 - Prob. 5CRCh. 10 - Prob. 6CRCh. 10 - Prob. 7CRCh. 10 - Prob. 8CRCh. 10 - Prob. 9CRCh. 10 - Prob. 10CRCh. 10 - Prob. 11CRCh. 10 - Prob. 12CRCh. 10 - Prob. 13CRCh. 10 - Prob. 14CRCh. 10 - Prob. 15CRCh. 10 - Prob. 16CRCh. 10 - Prob. 17CRCh. 10 - Prob. 18CRCh. 10 - Prob. 19CRCh. 10 - Prob. 20CRCh. 10 - Prob. 21CRCh. 10 - Prob. 22CRCh. 10 - Prob. 23CRCh. 10 - Prob. 24CRCh. 10 - Prob. 25CRCh. 10 - Prob. 26CRCh. 10 - Prob. 1CTCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 14CTCh. 10 - Prob. 15CTCh. 10 - Prob. 1CSTCh. 10 - Prob. 2CSTCh. 10 - Prob. 3CSTCh. 10 - Prob. 4CSTCh. 10 - Prob. 5CSTCh. 10 - Prob. 6CSTCh. 10 - Prob. 7CSTCh. 10 - Prob. 8CSTCh. 10 - Prob. 9CSTCh. 10 - Prob. 10CSTCh. 10 - Prob. 11CSTCh. 10 - Prob. 12CSTCh. 10 - Prob. 2PTTSCh. 10 - Prob. 3PTTSCh. 10 - Prob. 4PTTSCh. 10 - Prob. 5PTTSCh. 10 - Prob. 6PTTSCh. 10 - Prob. 7PTTSCh. 10 - Prob. 8PTTSCh. 10 - Prob. 9PTTSCh. 10 - Prob. 10PTTSCh. 10 - Prob. 11PTTSCh. 10 - Prob. 12PTTSCh. 10 - Prob. 13PTTSCh. 10 - Prob. 14PTTSCh. 10 - Prob. 15PTTSCh. 10 - Prob. 16PTTSCh. 10 - Prob. 1CPCh. 10 - Prob. 2CPCh. 10 - Prob. 3CPCh. 10 - Prob. 4CPCh. 10 - Prob. 5CPCh. 10 - Prob. 6CPCh. 10 - Prob. 7CPCh. 10 - Prob. 8CPCh. 10 - Prob. 9CPCh. 10 - Prob. 10CPCh. 10 - Prob. 11CPCh. 10 - Prob. 12CPCh. 10 - Prob. 13CPCh. 10 - Prob. 14CPCh. 10 - Prob. 16CPCh. 10 - Prob. 17CPCh. 10 - Prob. 18CPCh. 10 - Prob. 19CPCh. 10 - Prob. 20CPCh. 10 - Prob. 21CPCh. 10 - Prob. 22CPCh. 10 - Prob. 23CPCh. 10 - Prob. 25CPCh. 10 - Prob. 26CPCh. 10 - Prob. 27CPCh. 10 - Prob. 28CPCh. 10 - Prob. 29CPCh. 10 - Prob. 30CPCh. 10 - Prob. 31CPCh. 10 - Prob. 32CPCh. 10 - Prob. 33CPCh. 10 - Prob. 34CP
Additional Math Textbook Solutions
Find more solutions based on key concepts
Draining a tank An inverted conical water tank with a height of 12 ft and a radius of 6 ft is drained through a...
Calculus: Early Transcendentals (2nd Edition)
The table by using the given graph of h.
Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)
Express the side length of a square as a function of the length d of the square’s diagonal. Then express the ar...
University Calculus: Early Transcendentals (4th Edition)
whether the relation is a function
Pre-Algebra Student Edition
69. Get Started Early! Mitch and Bill are both age 75. When Mitch was 25 years old, he began depositing $1000 p...
Using and Understanding Mathematics: A Quantitative Reasoning Approach (6th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.Similar questions
- Listen Solve the quadratic equation. Write the smaller answer first. 2 Xx - 5x = 24 x = Α x =arrow_forwardSolve the absolute equation |2x = 4| = 10 ○ a) x = -7, x = 3 ○ b) x = -2, x = 6 ○ c) x = -3, x = 7 ○ d) x = 7arrow_forwardFind a rational inequality that has the solution set (-2, 5] О a) x-5 x+2 b) x+5 x-2 ΛΙ ≥ 0 < 0 VI О c) x-5 x+2 ≤0 VI ○ d) x +2 x-5 <0arrow_forward
- 1) Listen Solve the quadratic equation by factoring. One solution is O. Find the other. (Just write the numerical answer, not x =) 2x² + 28x = 0 Your Answer:arrow_forward4. Solve the system of equations and express your solution using vectors. 2x1 +5x2+x3 + 3x4 = 9 -x2+x3 + x4 = 1 -x1-6x2+3x3 + 2x4 = -1arrow_forward3. Simplify the matrix expression A(A-B) - (A+B)B-2(A - B)2 + (A + B) 2arrow_forward
- [2 pts] 1. Let A = [. 1 -1 0 -343 and B = 05 5 -7 304 Compute (7A - 3B) - 4(2A - B).arrow_forward20 2. Let A = = [ -2 0 1 3 ] and B = 2 3 -1 2 For each of the following, calculate the product or indicate why it is undefined: (a) AB (b) BAarrow_forwardAnswer the number questions with the following answers +/- 2 sqrt(2) +/- i sqrt(6) (-3 +/-3 i sqrt(3))/4 +/-1 +/- sqrt(6) +/- 2/3 sqrt(3) 4 -3 +/- 3 i sqrt(3)arrow_forward
- 1 Matching 10 points Factor and Solve 1)x3-216 0, x = {6,[B]} 2) 16x3 = 54 x-[3/2,[D]] 3)x4x2-42 0 x= [ +/-isqrt(7), [F] } 4)x+3-13-9x x=[+/-1.[H]] 5)x38x2+16x=0, x = {0,[K}} 6) 2x6-10x-48x2-0 x-[0, [M], +/-isqrt(3)) 7) 3x+2x²-8 x = {+/-i sqrt(2), {Q}} 8) 5x³-3x²+32x=2x+18 x = {3/5, [S]} [B] [D] [F] [H] [K] [M] [Q] +/-2 sqrt(2) +/- i sqrt(6) (-3+/-3 i sqrt(3))/4 +/- 1 +/-sqrt(6) +/- 2/3 sqrt(3) 4 -3 +/- 3 i sqrt(3) [S]arrow_forwardThe only problems I need help with ae the last 8 ones, Thanksarrow_forwardGraph without using the calculator y-1 = | x+4 |arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSON
Contemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage Learning
Linear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSON
Introduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
What are the Different Types of Triangles? | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=1k0G-Y41jRA;License: Standard YouTube License, CC-BY
Law of Sines AAS, ASA, SSA Ambiguous Case; Author: Mario's Math Tutoring;https://www.youtube.com/watch?v=FPVGb-yWj3s;License: Standard YouTube License, CC-BY
Introduction to Statistics..What are they? And, How Do I Know Which One to Choose?; Author: The Doctoral Journey;https://www.youtube.com/watch?v=HpyRybBEDQ0;License: Standard YouTube License, CC-BY
Triangles | Mathematics Grade 5 | Periwinkle; Author: Periwinkle;https://www.youtube.com/watch?v=zneP1Q7IjgQ;License: Standard YouTube License, CC-BY
What Are Descriptive Statistics And Inferential Statistics?; Author: Amour Learning;https://www.youtube.com/watch?v=MUyUaouisZE;License: Standard Youtube License