Pre-Algebra

1st Edition

ISBN: 9780618800766

Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold

Publisher: Houghton Mifflin-High School

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Question

Chapter 10.4, Problem 6E

(1)

To determine

To calculate the Area of entire mat.

(1)

Expert Solution

Answer to Problem 6E

144 m²

Explanation of Solution

Given Information: Length = 12 m and Breadth = 12 m

Formula Used:Area of rectangle = Length×Breadth

Calculation:

Length = 12 m and Breadth = 12 m

Area of rectangle = Length×Breadth

So,

Area of Mat = 12×12 m²

Hence,

Area of Mat = 144 m²

(2)

To determine

To calculate the Area of circle use to competition.

(2)

Expert Solution

Answer to Problem 6E

63.64 m²

Explanation of Solution

Given Information: Diameter = 9 m

Formula Used:Area of circle = π×r2 , radius=diameter2

Calculation:

Diameter = d, Radius = r.

Now, diameter is of 9 m.

So, radius=diameter2

Put the value of diameter to find the radius.

radius=92 m

Hence,

radius=4.5 m

Area of circle = π×r2

Area of circle = π×(4.5)2 m²

Now, π=227

Put the value of π to find the area

Area of competition circle = 227×4.5×4.5 m²

Area of competition circle = 63.64m²

(3)

To determine

Tocalculate to subtract area of Mat to area of competition used.

(3)

Expert Solution

Answer to Problem 6E

80.36 m²

Explanation of Solution

Given Information: Area of Mat and Area of circle used for competition

Formula Used:Remaining Area = Area of Mat - Area of competition circle

Calculation:

Area of Mat = 144 m²

Area of competition circle = 63.64 m²

Remaining Area = Area of Mat - Area of competition circle

So,

Remaining Area = 144 m² - 63.64 m²

Hence,

Remaining Area = 144 m² − 80.36 m²

Chapter 10.4, Problem 5E

Chapter 10.4, Problem 7E

Chapter 10 Solutions

Pre-Algebra

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

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