Pre-Algebra

1st Edition

ISBN: 9780618800766

Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold

Publisher: Houghton Mifflin-High School

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Concept explainers

Cylinders

A cylinder is a three-dimensional solid shape with two parallel and congruent circular bases, joined by a curved surface at a fixed distance. A cylinder has an infinite curvilinear surface.

Cones

A cone is a three-dimensional solid shape having a flat base and a pointed edge at the top. The flat base of the cone tapers smoothly to form the pointed edge known as the apex. The flat base of the cone can either be circular or elliptical. A cone is dr…

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Question

Chapter 10.6, Problem 18E

To determine

To calculate the surface area of cone.

Expert Solution & Answer

Answer to Problem 18E

594 ft²

Explanation of Solution

Given Information: Cone Diameter d = 18 ft., Slant Height l = 12 ft. and π=227

Formula Used:

Surface area of Cone = πr2+ πrl , Radius = Diameter2

Calculation:

Surface area of Cone = πr2+ πrl

Diameter d = 18 ft., Slant Height l = 12 ft. and π=227

First find Radius r.

Hence,

Radius = Diameter2

Put the value of diameter to find radius of Cone

Radius = 182

So,

Radius r = 9 ft.

Now put the value of r, s and π to find Surface area of Cone

Surface area of Cone = 227×92 + 227×9×12 ft²

So,

Surface area of Cone = 227×81 + 227×108 ft²

So,

Surface area of Cone = 227×(81 + 108) ft²

So,

Surface area of Cone = 227×189 ft²

Hence,

Surface area of Cone = 594 ft²

Nearest Surface area of Cone = 594 ft²

Chapter 10.6, Problem 17E

Chapter 10.6, Problem 19E

Chapter 10 Solutions

Pre-Algebra

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

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