The Lewis structure of hydroxylamine ( NH 3 O ) is to be drawn. Concept introduction: To draw the Lewis structure of the molecule there are following steps: Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom. Step 2: Calculate the total number of valence electrons. Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond. Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

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Chapter 10.1, Problem 10.2AFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of hydroxylamine (NH3O) is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the dimethyl ether (C2H6O) without the O−H bond is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

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