Chapter 10, Problem 90E

Interpretation Introduction

Interpretation:

A gas of unknown molecular mass is given to be allowed to effuse through a small opening under constant pressure condition. The gas has been given to require $105\text{s}$ for $1$ litre of it to effuse.
The given unknown gas under identical experimental condition requires $31\text{s}$ for $1$ litre of ${\text{O}}_2$ gas. The molar mass of unknown gas is to be stated.

Concept introduction: According to Graham’s law the rate of effusion of two gases under constant pressure and temperature condition is given by,
$\frac{r_1}{r_2}=\sqrt{\frac{{\text{M}}_2}{{\text{M}}_1}}$

To determine: The molar mass of given gas having unknown molecular mass.