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Concept explainers
Interpretation:
The molecular geometry of each of the given polyatomic ions or molecules is to be determined.
Concept Introduction: To determine the molecular geometry of a polyatomic ion, consider the total number of electron groups, the number of bonding groups and the number of lone pairs.
While writing the Lewis structure of a covalent molecule these steps are followed:
First, correct skeleton is written for the molecule
Total number of valence electrons are calculated
Distribution of a total number of valence electrons in such a way that it completes the octet configuration of all the constituent atoms.
If any atom lacks the octet configuration the double or triple bonds are added.
For molecules which obey the octet rule must have eight electrons in their valence shell. In the molecule, the total number of electron groups around the central atom is equal to the sum of lone pairs, a single bond, a double bond and triple bond around the central atom. On the basis of electron groups, the molecular geometry is predicted. To determine the geometry of the molecule, follow the following table:
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Chapter 10 Solutions
Introductory Chemistry (5th Edition) (Standalone Book)
- Nonearrow_forwardTransmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)arrow_forwardNonearrow_forward
- Draw the Lewis structure of C2H4Oarrow_forwarda) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forward
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