College Physics (10th Edition)
10th Edition
ISBN: 9780321902788
Author: Hugh D. Young, Philip W. Adams, Raymond Joseph Chastain
Publisher: PEARSON
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Chapter 10, Problem 73PP
Torques and tug-of-war. In a study of the biomechanics of the tug-of-war, a 2.0-m-tall, 80.0 kg competitor in the middle of the line is considered to be a rigid body leaning back at an angle of 30.0° to the vertical (Figure 10.81). The competitor is pulling on a rope that is held horizontal a distance of 1.5 m from his feet (as measured along the line of the body). At the moment shown in the figure, the man is stationary and the tension in the rope in front of him is T1 = 1160 N. Since there is friction between the rope and his hands, the tension in the rope behind him, T2, is not equal to T1. His center of mass is halfway between his feet and the top of his head. The coefficient of static friction between his feet and the ground is 0.65.
Figure 10.81
Problems 73–76
73. What is the tension T2 in the rope behind him?
- A. 590 N
- B. 650 N
- C. 860 N
- D. 1100 N
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Useful equations
For Constant Velocity:
V =>
D
X = V₁t + Xo
For Constant Acceleration:
Vr = V + at
X = Xo+Vot +
v=V+2a(X-Xo)
\prom = V +V
V velocity
t = time
D Distance
X = Final Position
Xo Initial Position
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a = acceleration
For free fall
Yf
= Final Position
Yo Initial Position
g = 9.80
m
$2
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+gt
V,² = V₁²+2g (Y-Yo)
V+Vo
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Solve the problems
Chapter 10 Solutions
College Physics (10th Edition)
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