Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Chapter 10, Problem 6C
To determine
What is the wavelength of the first member of the Balmer series? Wavelength of the photon emitted by the hydrogen, in what part of EM spectrum does this lie? Wavelength of photon require to ionize a hydrogen atom?
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A photoelectron is emitted from K shell (n = 1) of a carbon atom, and an election in L shell (n = 2) moves down to the vacancy in K shell. What is the wavelength, in the unit of nm, of the photon emitted during this transition?
Use for the energy difference between two states in an atom.
E0 = 13.6 eV and atomic number of carbon is Z = 12.
Use σ = 1 for the transition to K shell and σ = 7.4 for the transition to L shell
a. The electron of a hydrogen atom is excited into a higher energy level from a lower energy level. A short time later the electron relaxes down to the no = 1 energy level, releasing a
photon with a wavelength of 93.83 nm. Compute the quantum number of the energy level the electron relaxes from, nhi. Note: the Rydberg constant in units of wavenumbers is 109,625
cm-1
nhi =16
b. What would the wavenumber, wavelength and energy of the photon be if instead no = 1 and nhi = 4?
V: 6.9121e14 x (cm-¹)
λ:
(nm)
E: 45.8e-20
✓ (1)
Even before Neils Bohr's model of the hydrogen atom, it was observed that the wavelengths
emitted by hydrogen are predicted by an equation based on integer numbers (the Rydberg
equation). What wavelength does this equation predict for a transition of an electron in a hydrogen
atom from n = 6 to n = 2?
A =
nm
The Paschen series is a set of wavelengths emitted by hydrogen (in the infrared) corresponding to
transitions down to n = 3 (from n >3). What value of n >3 corresponds to A = 1,875 nm?
(Enter an integer)
n=
Chapter 10 Solutions
Inquiry into Physics
Ch. 10 - Prob. 1SACh. 10 - Prob. 1OACh. 10 - Prob. 1PIPCh. 10 - Prob. 1MIOCh. 10 - Prob. 2MIOCh. 10 - Prob. 1QCh. 10 - Prob. 2QCh. 10 - Prob. 3QCh. 10 - Prob. 4QCh. 10 - Prob. 5Q
Ch. 10 - Prob. 6QCh. 10 - Prob. 7QCh. 10 - Prob. 8QCh. 10 - Prob. 9QCh. 10 - Prob. 10QCh. 10 - Prob. 11QCh. 10 - (Indicates a review question, which means it...Ch. 10 - Prob. 13QCh. 10 - Prob. 14QCh. 10 - (Indicates a review question, which means it...Ch. 10 - Prob. 16QCh. 10 - Prob. 17QCh. 10 - Prob. 18QCh. 10 - Prob. 19QCh. 10 - Prob. 20QCh. 10 - Prob. 21QCh. 10 - Prob. 22QCh. 10 - Prob. 23QCh. 10 - Prob. 24QCh. 10 - Prob. 25QCh. 10 - Prob. 26QCh. 10 - Prob. 27QCh. 10 - Prob. 28QCh. 10 - Prob. 29QCh. 10 - Prob. 30QCh. 10 - Prob. 31QCh. 10 - Prob. 32QCh. 10 - Prob. 33QCh. 10 - Prob. 34QCh. 10 - Prob. 35QCh. 10 - Prob. 36QCh. 10 - Prob. 37QCh. 10 - Prob. 38QCh. 10 - Prob. 39QCh. 10 - Prob. 40QCh. 10 - Prob. 41QCh. 10 - Prob. 42QCh. 10 - Prob. 1PCh. 10 - Prob. 2PCh. 10 - Prob. 3PCh. 10 - Prob. 4PCh. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - Prob. 8PCh. 10 - Prob. 9PCh. 10 - Prob. 10PCh. 10 - Prob. 11PCh. 10 - Prob. 12PCh. 10 - . Figure 10.47 is the energy-level diagram for a...Ch. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - Prob. 18PCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 1CCh. 10 - Prob. 2CCh. 10 - The rate at which solar wind particles enter the...Ch. 10 - Prob. 4CCh. 10 - Prob. 5CCh. 10 - Prob. 6C
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- The work function for potassium is 2.26 eV. What is the cutoff frequency when this metal is used as photoelectrode? What is the stopping potential when for the emitted electrons when this photo electrode is exposed to radiation of frequency 1200 THz?arrow_forwardDerive an expression for the ratio of X-ray photon frequency for two elements with atomic numbers Z1 and Z2.arrow_forwardMeasurements indicate that an atom remains in an excited state for an average time of 50.0 ns before making a transition to the ground state with the simultaneous emission of a 2.1-eV photon. (a) Estimate the uncertainty in the frequency of the photon. (b) What fraction of the photon's average frequency is this?arrow_forward
- In extreme-temperature environments, such as those existing in a solar corona, atoms may be ionized by undergoing collisions with other atoms. One example of such ionization in the solar corona is the presence of C5+ ions, detected in the Fraunhofer spectrum. (a) By what factor do the energies of the C5+ ion scale compare to the energy spectrum of a hydrogen atom? (b) What is the wavelength of the first line in the Paschen series of C5+ ? (c) In what part of the spectrum are these lines located?arrow_forwardThe ion Li2+ makes ail atomic transition from ail n = 4 state to ail n = 2 state, (a) What is the energy of the photon emitted during the transition? (b) What is the wavelength of the photon?arrow_forward(a) What is the minimum value of l for a subshell that contains 11 electrons? (b) If this subshell is in the n = 5 shell, what is the spectroscopic notation for this atom?arrow_forward
- For an electron in a hydrogen atom in the n=2 state, compute: (a) the angular momentum; (b) the kinetic energy; (c) the potential energy; and (d) the total energy.arrow_forward(a) If one subshell of an atom has nine electrons in it, what is the minimum value of (b) What is the spectroscopic notation for this atom, if this subshell is part of the n = 3 shell?arrow_forwardConsider hydrogen in the ground state, 100 . (a) Use the derivative to determine the radial position for which the probability density, P(r), is a maximum. (b) Use the integral concept to determine the average radial position. (This is called the expectation value of the electrons radial position.) Express your answers into terms of the Bohr radius, a0. Hint: The expectation value is the just average value, (c) Why are these values different?arrow_forward
- The K series of the discrete spectrum of tungsten contains wavelengths of 0.0185 nm, 0.0209 nm, and 0.0215 nm. The K-shell ionization energy is 69.5 keV. Determine the ionization energies of the L, M, and N shells. kev EL = 11.83 kev 2.4 Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. ke EN EM = 10.17 %Darrow_forwardThe light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forwardSeven possible transitions are identified on the energy-level diagram as shown. For each, is this an allowed transition? If allowed, is it an emission or an absorption transition, and is the photon infrared, visible, or ultraviolet? If not allowed, why not?arrow_forward
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