Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
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Chapter 10, Problem 34Q
To determine
What are the two parts in the x-ray spectrum of a heavy elements? How they are produced?
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Chapter 10 Solutions
Inquiry into Physics
Ch. 10 - Prob. 1SACh. 10 - Prob. 1OACh. 10 - Prob. 1PIPCh. 10 - Prob. 1MIOCh. 10 - Prob. 2MIOCh. 10 - Prob. 1QCh. 10 - Prob. 2QCh. 10 - Prob. 3QCh. 10 - Prob. 4QCh. 10 - Prob. 5Q
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- Arrange the following according to their ability to act as radiation shields, with the best first and worst last. Explain your ordering in terms of how radiation loses its energy in matter. (a) A solid material with low density composed of low-mass atoms. (b) A gas composed of highmass alums. (c) A gas composed of lowmass atoms. (d) A solid with high density composed of highmass atoms.arrow_forwardLook at the chemical elements in Appendix K. Can you identify any relationship between the abundance of an element and its atomic weight? Are there any obvious exceptions to this relationship?arrow_forward(Indicates a review question, which means it requires only a basic understanding of the material to answer. Questions without this designation typically involve integrating or extending the concepts presented thus far.) . A mixture of hydrogen and neon is heated until it is luminous. Describe what is seen when this light passes through a prism and is projected onto a screen.arrow_forward
- Can you solve the question clearly ?arrow_forward6.1 Derive the relationship between half value layer (HVL) and linear attenuation coefficient (μ). 6.2 Calculate the thickness of aluminum required to reduce the intensity of a 200 keV gamma-ray beam to 40% of its incident intensity? Assume that the HVL for 200 keV gamma-rays is 2,14 cm Al. 6.3 Draw a graph to illustrate how a mono-energetic photon beam is attenuated through four HVL thicknesses of Al (Aluminium).arrow_forwardSuppose an unknown element has an absorption spectrum with lines corresponding to 2.5, 4.7, and 5.1 eV aboveits ground state and an ionization energy of 11.5 eV. Drawan energy level diagram for this element. (b) If a 5.1-eVphoton is absorbed by an atom of this substance, in whichstate was the atom before absorbing the photon? What willbe the energies of the photons that can subsequently beemitted by this atom?arrow_forward
- I need help trying to figgure out how to fill out the graph by just using the info on the grapharrow_forwardUnit 1: 1. Explain the generation of X-rays with basic requirements. 2. Explain how the characteristic X-rays are produced.arrow_forwardThis is one question with 3 parts so it is not against guidelines to answer all 3 parts. Please use simplistic terminology for the answers doesn’t have to to be long. Your are looking at 27-29arrow_forward
- I have a 7 question final exam and all of questions bond to each other. Can you help me solving them? And you need to use the constants on the second image. This is the first one and second one. Please help me The mass difference between two isotopes is sometimes just a neutron mass. The spectrometer should separate them very well. For such an isotope combination, the difference in radius should be around 1 cm. That is . In order to achieve this, choose a magnetic field with a magnitude in Tesla (maximum magnetic field you can obtain from a conventional magnet is around 2.5 T so be far away from this value) and choose the direction also. Then determine the velocity of isotope you need. Last calculate radius r of a smallest isotope. In order to produce this magnetic field, determine the current and number of turns, radius and other parameters of a solenoid you need. Also show how you will position this solenoid.arrow_forwardP6arrow_forward1 For the Rutherford (Geiger and Marsden) experiment with 5.5 MeV alpha particles on a 1 um gold foil, and for the six angles (decades) between 10-5 and 10° rad, calculate the Rutherford differential cross section (DCS), dor/d2, (a) without and (b) with screening. Represent both results graphically and draw conclusions. Answer: The nonscreened DCS values vary between 1.7137x10-3 and 2.0273×10 23 cm? rad-' in the interval [10-5-1 rad]. The screening angle is 3.7 x 10-3 rad, and the corresponding screened DCS values vary between 9.3620 x 10-14 and 2.0273 x 10-23 cm² rad-'. The screening Xa cuts off the otherwise increasing DCS with decreasing angle, which remains practically constant below Xarrow_forward
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