EBK FOUNDATIONS OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119227946
Author: Willard
Publisher: VST
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Question
Chapter 10, Problem 58AE
Interpretation Introduction
Interpretation:
The complete and short hand electronic configuration of Bismuth has to be given.
Concept Introduction:
Aufbau’s principle:
Aufbau’s principle states that electrons are filled into atomic orbitals in the increasing order of orbital energy level. According to the Aufbau principle the available atomic orbitals with the lowest energy levels are occupied before those with higher energy levels.
Figure 1
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Students have asked these similar questions
4. A. Use the list of intermolecular and interparticle forces listed below to account for the following
phenomena. Justify your answer in each case.
London Dispersion Forces
lonic Bonding
Dipole-Dipole Interactions
Metallic Bonding
Hydrogen Bonding
Covalent Bonding
(i) Nacl has a very high heat of vaporization.
(ii) The high volatility of helium (boiling point is - 267 °C, lowest of any element).
(iii) What are the strongest attractive forces that must be overcome to boil carbon tetrachloride,
(CCl,)?
B. Read the following statement: NaF has a higher melting point than F2 because it has a greater molar
mass. Do you agree with the statement? Explain why you believe the statement is true or falsr
Based on the type or types of intermolecular forces, predictthe substance in each pair that has the higher boiling point:(a) propane (C3H8) or n-butane (C4H10), (b) diethyl ether(CH3CH2OCH2CH3) or 1-butanol (CH3CH2CH2CH2OH),(c) sulfur dioxide (SO2) or sulfur trioxide (SO3), (d) phosgene(Cl2CO) or formaldehyde (H2CO).
Name the type(s) of intermolecular forces that exists between molecules (or basic units) in each of the following species and identify the following species that are capable of hydrogen-bonding among themselves.
(a) BeH2, (b) CH3COOH
Chapter 10 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY
Ch. 10.1 - Prob. 10.1PCh. 10.2 - Prob. 10.2PCh. 10.3 - Prob. 10.3PCh. 10.4 - Prob. 10.4PCh. 10.5 - Prob. 10.5PCh. 10.5 - Prob. 10.6PCh. 10.5 - Prob. 10.7PCh. 10 - Prob. 1RQCh. 10 - Prob. 2RQCh. 10 - Prob. 3RQ
Ch. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQCh. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13RQCh. 10 - Prob. 14RQCh. 10 - Prob. 15RQCh. 10 - Prob. 16RQCh. 10 - Prob. 17RQCh. 10 - Prob. 18RQCh. 10 - Prob. 19RQCh. 10 - Prob. 20RQCh. 10 - Prob. 21RQCh. 10 - Prob. 22RQCh. 10 - Prob. 23RQCh. 10 - Prob. 24RQCh. 10 - Prob. 25RQCh. 10 - Prob. 1PECh. 10 - Prob. 2PECh. 10 - Prob. 3PECh. 10 - Prob. 4PECh. 10 - Prob. 5PECh. 10 - Prob. 6PECh. 10 - Prob. 7PECh. 10 - Prob. 8PECh. 10 - Prob. 9PECh. 10 - Prob. 10PECh. 10 - Prob. 11PECh. 10 - Prob. 12PECh. 10 - Prob. 13PECh. 10 - Prob. 14PECh. 10 - Prob. 15PECh. 10 - Prob. 16PECh. 10 - Prob. 17PECh. 10 - Prob. 18PECh. 10 - Prob. 19PECh. 10 - Prob. 20PECh. 10 - Prob. 21PECh. 10 - Prob. 22PECh. 10 - Prob. 23PECh. 10 - Prob. 24PECh. 10 - Prob. 25PECh. 10 - Prob. 26PECh. 10 - Prob. 27PECh. 10 - Prob. 28PECh. 10 - Prob. 29PECh. 10 - Prob. 30PECh. 10 - Prob. 31PECh. 10 - Prob. 32PECh. 10 - Prob. 33PECh. 10 - Prob. 34PECh. 10 - Prob. 35PECh. 10 - Prob. 36PECh. 10 - Prob. 37PECh. 10 - Prob. 38PECh. 10 - Prob. 39PECh. 10 - Prob. 40PECh. 10 - Prob. 41PECh. 10 - Prob. 42PECh. 10 - Prob. 43PECh. 10 - Prob. 44PECh. 10 - Prob. 45PECh. 10 - Prob. 46PECh. 10 - Prob. 47PECh. 10 - Prob. 48PECh. 10 - Prob. 49PECh. 10 - Prob. 50PECh. 10 - Prob. 51AECh. 10 - Prob. 52AECh. 10 - Prob. 53AECh. 10 - Prob. 54AECh. 10 - Prob. 57AECh. 10 - Prob. 58AECh. 10 - Prob. 59AECh. 10 - Prob. 60AECh. 10 - Prob. 61AECh. 10 - Prob. 62AECh. 10 - Prob. 63AECh. 10 - Prob. 64AECh. 10 - Prob. 65AECh. 10 - Prob. 66AECh. 10 - Prob. 67AECh. 10 - Prob. 68AECh. 10 - Prob. 69AECh. 10 - Prob. 70AECh. 10 - Prob. 71AECh. 10 - Prob. 72AECh. 10 - Prob. 73AECh. 10 - Prob. 74AECh. 10 - Prob. 75AECh. 10 - Prob. 76AECh. 10 - Prob. 77AECh. 10 - Prob. 78CECh. 10 - Prob. 79CECh. 10 - Prob. 80CECh. 10 - Prob. 81CECh. 10 - Prob. 82CE
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Similar questions
- Predict which liquid—glycerol, HOCH2CH(OH)CH2OH, or hexane, C6H14—has the greater surface tension. Explain your prediction.arrow_forwardWhich of the following compounds would be expected to form intermolecular hydrogen bonds in the liquid state? (a) H2Se (b) HCO2H (formic acid) (c) HI (d) acetone, (CH3)2COarrow_forwardSilane SiH4, phosphine (PH3), and hydrogen sulfide (H2S) melt at 185 C, 133 C, and 85 C, respectively. What does this suggest about the polar character and intermolecular attractions of the three compounds?arrow_forward
- The compounds ethanol (C2H5OH) and dimethyl ether (CH3OCH3) have the same molecular formula. Which is expected to have the higher surface tension? Why?arrow_forwardDefine the following terms and describe how each depends on the strength of the intermolecular forces. a. surface tension b. viscosity c. melting point d. boiling point e. vapor pressurearrow_forwardPlace the intermolecular attractions in order of their increasing strength and explain why. : CH3COOH , Ar, Cl2, and CH4arrow_forward
- Which kind of intermolecular attractive force is shownin each case here?arrow_forwardSilane (SiH4), phosphine (PH3), and hydrogen sulfide (H2S) melt at −185 °C, −133 °C, and −85 °C, respectively. What does this suggest about the polar character and intermolecular attractions of the three compounds?arrow_forwardIn which of these substances is hydrogen bonding likely to play an important role in determining physical properties: methane(CH4), hydrazine (H2NNH2), methyl fluoride (CH3F), hydrogen sulfide (H2S)?arrow_forward
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