Essential Organic Chemistry (3rd Edition)
Essential Organic Chemistry (3rd Edition)
3rd Edition
ISBN: 9780321937711
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Chapter 10, Problem 57P
Interpretation Introduction

Interpretation:

The compound that could have C=O at higher frequency has to be identified and explained.

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Why do aldehydes, esters, and amides all have a strong absorption in the 1630-1780 cm1 region of their IR spectra? A) The bond between H and the sp³-hybridized C in these functional groups vibrates in this energy range. B) Each of these functional groups has at least two resonance structures, and the different vibrations of the resonance structures give off energy in this region. C) The bond between O and the sp²-hybridized C in these functional groups vibrates at a frequency in this energy range. D) Light at this wavenumber causes the average C to O bond length to increase which causes more of this light to be transmitted. E) An electron in the bond of these functional groups gets excited to the * orbital.
4. Why does a carbon to oxygen double bond absorption band have a greater intensity than a carbon to carbon double bond absorption band?
Norlutin and Enovid are ketones that suppress ovulation, so they have been used clinically as contraceptives. For which of these compounds would you expect the infrared carbonyl absorption (C=O stretch) to be at a higher frequency? Explain.

Chapter 10 Solutions

Essential Organic Chemistry (3rd Edition)

Ch. 10.6 - Identify the ketone responsible for the mass...Ch. 10.6 - Prob. 13PCh. 10.8 - Prob. 14PCh. 10.8 - Prob. 15PCh. 10.12 - Which will occur at a larger wavenumber: a. a C :...Ch. 10.13 - Which will occur at a larger wavenumber: a. the C...Ch. 10.13 - Prob. 18PCh. 10.13 - Prob. 19PCh. 10.13 - Which will show an O 8 H stretch at a larger...Ch. 10.14 - Prob. 21PCh. 10.14 - Prob. 22PCh. 10.15 - Prob. 23PCh. 10.15 - Prob. 24PCh. 10.17 - Prob. 25PCh. 10.18 - Prob. 26PCh. 10.18 - Prob. 27PCh. 10.19 - Prob. 28PCh. 10.19 - Prob. 29PCh. 10.22 - How many signals would you expect to see in the 1H...Ch. 10.22 - Prob. 31PCh. 10.22 - Prob. 32PCh. 10.23 - Where would you expect to find the 1H NMR signal...Ch. 10.24 - Prob. 34PCh. 10.25 - Prob. 35PCh. 10.25 - Prob. 36PCh. 10.25 - Prob. 37PCh. 10.26 - Prob. 38PCh. 10.26 - Which of the following compounds is responsible...Ch. 10.27 - Prob. 40PCh. 10.27 - Prob. 41PCh. 10.27 - The 1H NMR spectra of two carboxylic acids with...Ch. 10.28 - Prob. 43PCh. 10.28 - Prob. 44PCh. 10.28 - Prob. 45PCh. 10.28 - Describe the 1H NMR spectrum you would expect for...Ch. 10.28 - Identify the compound with molecular formula...Ch. 10.29 - Prob. 48PCh. 10.29 - Prob. 49PCh. 10.29 - Identify the compound with a molecular formula of...Ch. 10 - In the mass spectrum of the following compounds,...Ch. 10 - For each of the following pairs of compounds,...Ch. 10 - Draw the structure of a saturated hydrocarbon that...Ch. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - How could you use UV spectroscopy to distinguish...Ch. 10 - Prob. 57PCh. 10 - Predict the relative intensities of the molecular...Ch. 10 - Prob. 59PCh. 10 - List the following compounds in order from highest...Ch. 10 - How can 1H NMR be used to prove that the addition...Ch. 10 - There are four esters with molecular formula...Ch. 10 - Prob. 63PCh. 10 - Prob. 64PCh. 10 - Each of the IR spectra presented here is...Ch. 10 - Prob. 66PCh. 10 - Five compounds are shown for each of the following...Ch. 10 - Prob. 68PCh. 10 - Prob. 69PCh. 10 - Phenolphthalein is an acidbase indicator. In...Ch. 10 - Which one of the following five compounds produced...Ch. 10 - Prob. 72PCh. 10 - Prob. 73PCh. 10 - Prob. 74PCh. 10 - How could 1H NMR distinguish between the compounds...Ch. 10 - Prob. 76PCh. 10 - Prob. 77PCh. 10 - The 1H NMR spectra of three isomers with molecular...Ch. 10 - The 1H NMR spectra of three isomers with molecular...Ch. 10 - Identify the following compounds. (Relative...Ch. 10 - An alkyl halide reacts with an alkoxide ion to...Ch. 10 - Determine the structure of a compound with...
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IR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=_TmevMf-Zgs;License: Standard YouTube License, CC-BY