Concept explainers
To test whether the dieters is managed to not to regain the weight they lost.
Explanation of Solution
Given the following information:
Given the weight of person before diet and after diet in pounds.
The test procedure:
The null and alternative hypothesis is given by
Where
The test statistic is given by,
Reject the null hypothesis if
Calculation:
before x | after y | d = x-y |
158 | 163 | -5 |
185 | 182 | 3 |
176 | 188 | -12 |
172 | 150 | 22 |
164 | 161 | 3 |
234 | 220 | 14 |
258 | 235 | 23 |
200 | 191 | 9 |
228 | 228 | 0 |
246 | 237 | 9 |
198 | 209 | -11 |
221 | 220 | 1 |
236 | 222 | 14 |
255 | 268 | -13 |
231 | 234 | -3 |
Mean of d | 3.6 |
SD of d | 11.52513 |
t | 0.312361 |
t cri | 1.76131 |
The above table is obtained from excel.
The value of test statistic t = 0.312361
Critical value of t at 0.05 level of significance = 1.76131
As t <1.76131, we do not reject the null hypothesis and conclude that the five-week crash diet is not effective over a long period of time.
Chapter 10 Solutions
The Practice of Statistics for AP - 4th Edition
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STATS:DATA+MODELS-W/DVD
Introductory Statistics (2nd Edition)
Statistics: The Art and Science of Learning from Data (4th Edition)
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