Chapter 10, Problem 26A

Interpretation Introduction

Interpretation: The specific heat capacity of the metal in $\text{J/g}\text{°C}$ needs to be determined.

Concept Introduction:The expression for heat is as follows:

  $Q=s\times m\times \Delta T$

Here, Q represents energy required, s denotes specific heat capacity, m represent mass of the sample in grams and $\Delta T$ represent change in temperature.

Answer to Problem 26A

The s value in $\text{J/g}\text{°C}$ is $6.02\text{J/g}°\text{C}$ .

Explanation of Solution

Given values are as follows:

  $\begin{array}{l}Q=69.5\text{kJ}\\ m=1012\text{g}\\ \Delta T=11.4°\text{C}\\ s=?\end{array}$

Convert Q values from kJ to J as follows:

  $\begin{array}{c}\text{1}\text{kJ=1000}\text{J}\\ \text{69}\text{.5}\text{kJ=}\frac{\text{1000}\text{J}\times \text{69}\text{.5}\text{kJ}}{1\text{kJ}}\\ =69500\text{J}\end{array}$

Substitute all values in below question and find s.

  $\begin{array}{c}Q=s\times m\times \Delta T\\ 69500\text{J}=s\times 1012\text{g}\times 11.4°\text{C}\\ s=\frac{69500\text{J}}{1012\text{g}\times 11.4°\text{C}}\\ =6.02\text{J/g}°\text{C}\end{array}$

Therefore, s value is $6.02\text{J/g}°\text{C}$ .