ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
10th Edition
ISBN: 9781260008562
Author: Carey
Publisher: MCG
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Chapter 10, Problem 23P
Interpretation Introduction
Interpretation:
The structural formulas of the two stereoisomers formed by the photochemical chlorination of
Concept introduction:
Enantiomers have the same connectivity of the atoms, but they have different arrangement of the atoms in space. They contain chiral centers and they are non-superimposable mirror images of each other.
Diastereoisomers are the stereoisomers but they are not the enantiomers with each other.
When one chirality center is present a molecule with no element of symmetry is said to be chiral molecule.
The ratio of the monochlorination products depends on the type of hydrogen that is abstracted by the chlorine atom and the free radical that is formed.
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Students have asked these similar questions
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
R lactam or lactone considering as weak acid or weak base and why
Chapter 10 Solutions
ORGANIC CHEMISTRY (LOOSELEAF)-PACKAGE
Ch. 10.1 - Prob. 1PCh. 10.1 - Prob. 2PCh. 10.2 - Use the data in Table 10.1 to calculate H for the...Ch. 10.3 - Prob. 4PCh. 10.4 - Prob. 5PCh. 10.4 - Prob. 6PCh. 10.4 - Do the arithmetic involved in converting the...Ch. 10.4 - How many constitutionally isomeric...Ch. 10.4 - Prob. 9PCh. 10.5 - Prob. 10P
Ch. 10.5 - Prob. 11PCh. 10.5 - Prob. 12PCh. 10.6 - Prob. 13PCh. 10.7 - Prob. 14PCh. 10.8 - Prob. 15PCh. 10 - Carboncarbon bond dissociation enthalpies have...Ch. 10 - Use the bond dissociation enthalpy data in Table...Ch. 10 - Use the bond dissociation enthalpy data in Table...Ch. 10 - Write the structure of the major organic product...Ch. 10 - Excluding enantiomers, free-radical chlorination...Ch. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Compound A (C6H14) gives three different...Ch. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Guiding your reasoning by retrosynthetic analysis,...Ch. 10 - (Z)-9-tricosene [(Z)-CH3(CH2)7CH=CH(CH2)12CH3] is...Ch. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34DSPCh. 10 - Prob. 35DSPCh. 10 - Prob. 36DSPCh. 10 - Prob. 37DSPCh. 10 - Prob. 38DSP
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