Among the given gases which one behaves ideally at given temperature and pressure conditions that is at 10 atm and -50 o C should be determined. Concept Introduction : Intramolecular force : The force of attraction that exists between bonds with in molecule. Than the ionic bond between two ions are formed from the transfer of electrons to another atom. Van der Waals' forces : This is electrostatic attraction between temporary dipoles and induced dipoles caused by moments of electrons in atoms and molecules. Ideal gas : The pressure (P), volume (V) number of moles of gas (n) and temperature (T), than the constant of equation shown is (R) known as the gas constant, this relationship between the them may be deduce from kinetic theory and is called the number of moles and (R) gas constant. To identify : The gas that is more ideal among the given two gases.

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A J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3

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Question

Chapter 10, Problem 17Q

Interpretation Introduction

Interpretation:

Among the given gases which one behaves ideally at given temperature and pressure conditions that is at 10 atm and -50oC should be determined.

Concept Introduction:

Intramolecular force: The force of attraction that exists between bonds with in molecule. Than the ionic bond between two ions are formed from the transfer of electrons to another atom.

Van der Waals' forces: This is electrostatic attraction between temporary dipoles and induced dipoles caused by moments of electrons in atoms and molecules.

Ideal gas: The pressure (P), volume (V) number of moles of gas (n) and temperature (T), than the constant of equation shown is (R) known as the gas constant, this relationship between the them may be deduce from kinetic theory and is called the number of moles and (R) gas constant.

To identify: The gas that is more ideal among the given two gases.

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A J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3

1. Answer the questions about the following reaction: (a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this reaction. Be sure to include any relevant stereochemistry in the product structure. + SK F Br + (b) In which solvent would this reaction proceed the fastest (Circle one) Methanol Acetone (c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest other products that are formed? Draw them in the box provided.

3. For the reactions below, draw the arrows corresponding to the transformations and draw in the boxes the reactants or products as indicated. Note: Part A should have arrows drawn going from the reactants to the middle structure and the arrows on the middle structure that would yield the final structure. For part B, you will need to draw in the reactant before being able to draw the arrows corresponding to product formation. A. B. Rearrangement ΘΗ