Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 10, Problem 10.8P
To determine
Calculate the effective friction angle.
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A consolidated-undrained test determines that the shear strength of a normally consolidated clay is given by τf = σ’tan 27o. The confining pressure is 150 kPa, and deviator stress at failure is 120 kPa.• Find the consolidated-undrained friction angle• Pore water pressure developed in the specimen at failureFinal answer should be in 3 decimal places.
5- The shear strength of a normally consolidated clay can be given by the equation tf o'tan 27°. Following are the
results of a
consolidated-undrained
test on the clay.
• Chamber-confining pressure = 3,130 lb/ft²
Deviator stress at failure = 2,510 lb/ft²
a) Determine the consolidated-undrained friction angle
b) Pore-water pressure developed in the specimen at failure
2. A triaxial shear test was performed on a well-drained sand
sample. The normal stress on the failure plane and the shear
stress on the failure plane, at failure was determined to be
6,300 psf and 4,200 psf, respectively.
a. Determine the angle of internal friction of the sand.
b. Determine the angle of failure plane.
c. Determine the maximum principal stress.
Chapter 10 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 10 - Prob. 10.1PCh. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10P
Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24CTPCh. 10 - Prob. 10.25CTP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- A series of previous CD tests conducted on a NC clay has established that the ultimate effective friction angle of the clay is 300. Now a CU test is conducted on this soil with an effective cell pressure of 100 kPa. The specimen fails at a deviatoric stress of 100 kPa. Estimate the pore pressure at failure. Given: σ3f′=Kaσ1f′whereKa=1−sinϕ1+sinϕ Please do fast .... ASAP Fastarrow_forwardA triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively. a. Determine the angle of internal friction of the sand? b. Determine the angle of the failure plane? c. Determine the maximum principal stress? Please answer this asap. For upvote. Thank you very mucharrow_forwardx in red is equal to 39arrow_forward
- A consolidated undrained triaxial test was performed on a normally consolidated clay with a critical state friction angle of 230. After an initial isotropic consolidation at a cell pressure of 50 kPa, drainage was turned off, the cell pressure was increased to 85 kPa, and the sample was loaded to ultimate conditions. A pore pressure of 55 kPa was measured at ultimate state. What value of major principal total stress was measured at the ultimate state?arrow_forwardsolve the question provided in the image.arrow_forwardFriction angle of dry sand is 35°. In a direct shear test on this sand, a normal stress of 150kPa was applied. What shear stress will cause the failure? (a) 150kPa (b) 50kPa (c) 78kPa (d) 105kPaarrow_forward
- The effective strength parameters for a clay are known to be cʹ = 15kPa and φʹ = 29°. A UU triaxial test and CUtriaxial test were performed on identical saturated samples of the same clay. In both cases, the cell pressure was 100 kPa. In the UU test, the deviator stress at failure was 98 kPa, and in the CU test, the deviator stress at failure was 264 kPa. Find:•The undrained shear strength, su, of the specimen from the UU test•The pore pressure in the specimen at failure in the UU test.•The value of the Skempton parameter A̅ f from the CU testarrow_forwardA clay specimen with drained shear strength parameters of c'=5 kPa and Φ=320 is consolidated under all around pressure of 140 kPa.The specimen was then loaded axially to failure under undrained condition and failed when the principal stress diffrences reached 60 kPa.Calculate the pore pressure(u) and the pore pressure coefficient D(=A*B=Δu/Δσv) of the clay.arrow_forwardA consolidated-undrained triaxial test was conducted on a saturated, normally consolidated clay. The test results areσ3 = 13 lb/in2σ1(failure) = 32 lb/in2Pore pressure at failure = u = 5.5 lb/in2. Determine c, Φ, c', and Φ'.arrow_forward
- ane shear test is used to determine the undrained shear strength of Ankara clay. If the clay is known to have a sensitivity ratio of 3 and undrained laboratory-based peak shear strength of cu=35 kPa, estimate the peak and the residual torques. The shear vane used in the test has a diameter of 75 mm and a height of 150 mmarrow_forwardPlease answer 12.17arrow_forward• In consolidated-drained triaxial test on a normally consolidated clay, the specimen failed at a deviator stress of 124 KN/sq.m. If the effective stress friction angle is known to be 31°, what was the effective confining pressure at failure?arrow_forward
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