Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 10, Problem 10.23P
To determine
Find the pore water pressure at failure for the unconfined compression test.
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Data from an oedometer test using a clay specimen are plotted in the graph shown below. If the compression index is equal to 0.6, calculate the void ratio (e2) missing at Point C, which is associated with a vertical effective stress equal to 105 kPa
A series of previous CD tests conducted on a NC clay has established that the ultimate effective friction angle of the clay is 300.
Now a CU test is conducted on this soil with an effective cell pressure of 100 kPa. The specimen fails at a deviatoric stress of 100 kPa. Estimate the pore pressure at failure.
Given: σ3f′=Kaσ1f′whereKa=1−sinϕ1+sinϕ
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Undisturbed samples from a normally consolidated clay layer were collected during a subsoil exploration .Drained triaxial tests showed that the effective friction angle was ? ′ = 25°. The unconfined compressive strength, ??, of a similar specimen was found to be 133 KN/m2 . Find the pore pressure at failure for the unconfined compression test.
Chapter 10 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 10 - Prob. 10.1PCh. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10P
Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24CTPCh. 10 - Prob. 10.25CTP
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- Problem # 5. The angle of friction of compacted dry sand is 37°. In a direct shear test on the sand, normal stress of 150 kN/m^2 was applied. The size of the specimen was 50mm x 50mm 30 mm (height): a. Compute the shearing stress.b. What shear force will cause will cause shear failure?c. Determine the shear stress at a depth 3m. If the void ratio of the soil is 0.60. Sp. Gr. of sand is 2.70.arrow_forwardA soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test, a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at additional stress of 160 kN/m2. Determine the angle made by the failure plane with the axial stress in the triaxial test. Hint: Draw the Mohr Circle. a.19 b.54.5 c.45.5 d.43arrow_forwardQ.64 In an unconfined compression test, a sample clay 100 mm and 50 mm in diameter fails under a load of 150 N at 10% strain. What is the shearing resistance taking into account the effect of change in cross-section of the sample? (a) 0.068 N/mm2 (c) 0.034 N/mm2 (b) 0.088 N/mm2 (d) 0.044 N/mm? Ans. (a)arrow_forward
- 2- A three-axis compression test on a clay sample that is comprehensive and normal up to a stress of 300 kPa and a specific volume of 2 Consolidated is done, The values of q and volumetric strain are measured at axial strain, 0, 2 and 10 percent (failure) . The value of N is equal to 3 and A is equal to 0.2. Graph of all-round stress on initial all-round stress Draw the initial all-round stress in terms of sectionarrow_forwardA consolidated-undrained triaxial compression test was performed on a normalconsolidated clay sample. During the experiment, the confining pressure was 140 kPa, thedeviator stress was 125 kPa, and the pore water pressure was 75 kPa at the time of failure.According to the information given:i- Find the consolidated-undrained internal friction angle of the clay. ii- Find the drained friction angle of the clayarrow_forwardx in red is equal to 39arrow_forward
- Please answer 12.17arrow_forwardA drained triaxial compression test on a saturated clay yielded the effective shear strength parameters as c' = 15 kPa and o'= 22°. %3D Consolidated Undrained triaxial test on an identical sample of this clay at a cell pressure of 200 kPa developed a pore water pressure of 150 kPa at failure. The deviator stress (expressed in kPa) at failure isarrow_forwardThe effective stress parameters for a fully saturated clay are known to be c'=10 kN/m- and Phi (internal friction angle) =29°. In an unconsolidated-undrained triaxial test on a specimen of the same clay the all-round pressure was 110KN/m- and the principal stress difference at failure was 190KN/m2. What was the value of pore water pressure in the specimen at failure? O A. The alue of pore water pressure in the specimen at failure = 29 kPa O B. The alue of pore water pressure in the specimen at failure = 22 kPa O C. The alue of pore water pressure in the specimen at failure = 20 kPa O D. The alue of pore water pressure in the specimen at failure = 27 kPaarrow_forward
- A = 45 B = 40 C = 15arrow_forwardThree specimnens of clay having a small air-void content were tested in the shear box. Shear loading was started immediately after the application of the normal load and was completed in 8 minutes. The results are as follows: Normal Stress (kN/m2) Shear stress at failure (kN/m2) O Find the apparent cohesion of the clay. Find the angle of shearing resistance of the clay. What value of c would be obtained from an unconfined compression test on 145 241 337 103 117 131 the same soil?arrow_forwardIn a tri-axial test of normally consolidated clay, the sample subjected to chamber confining pressure of 250 kPa and failed when deviator stress is 350 kPa. Which of the following gives the angle of internal friction? Which of the following gives the shear stress at failure? Which of the following gives the effective normal stress at maximum shear?arrow_forward
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