Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 10, Problem 10.2P
To determine
Find the angle of friction.
Find the required shear force to cause failure of the specimen.
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A direct shear test was conducted on a specimen of dry sand with a normal stress of 200 kN/m2. Failure occurred at a shear stress of 175 kN/m2. The size of the specimen testedwas 75 mm × 75 mm × 30 mm (height). Determine the angle of friction, . For a normal stress of 150 kN/m2, what shear force would be required to cause failure of the specimen?
Q # 3. Following data are given for a direct shear test conducted on dry sand:
Specimen dimensions: 63 mm x63 mm and 25 mm (height).
Normal stress: 105 kN/m?.
Shear force at failure: 300 N
a. Determine the angle of friction, for a normal stress of 180 kN/m?.
b. What shear force is required to cause failure?
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Chapter 10 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 10 - Prob. 10.1PCh. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10P
Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24CTPCh. 10 - Prob. 10.25CTP
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- The angle of friction of a compacted dry sand is 37 degrees. In a direct shear test on the sand, anormal stress of 150 kN/m^2 was applied. The size of the specimen was 50mmx50mx30mm(height) SITUATION 1 a. Compute the shearing stress Your answer b. What shear force will cause shear failure? Your answer c. Determine the shear stress at a depth of 3m if the void ratio of the soil is 0.60. Gs Of sand is 2.70arrow_forwardSoil Mechanismarrow_forwardPlease answer fast. Im struggling!arrow_forward
- Q # 3. Following data are given for a direct shear test conducted on dry sand: Specimen dimensions: 63 mm × 63 mm and 25 mm (height). Normal stress: 105 kN/m². Shear force at failure: 300 N Determine the angle of friction, for a normal stress of 180 kN/m². b. What shear force is required to cause failure? а.arrow_forward1 .For a direct shear test on a dry sand, the following are given:• Specimen size: 75 mm 75 mm 30 mm (height)• Normal stress: 200 kN/m2• Shear stress at failure: 175 kN/m2a. Determine the angle of friction, f b. For a normal stress of 150 kN/m2, what shear force is required to cause failure?in the specimearrow_forwardplease answer my homework problems. I will leave good review. thank you!arrow_forward
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