Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 10, Problem 10.14P
To determine
Find the pore water pressure within the specimen.
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A consolidated undrained triaxial test was
performed on a normally consolidated clay
with a critical state friction angle of 230. After
an initial isotropic consolidation at a cell
pressure of 50 kPa, drainage was turned off,
the cell pressure was increased to 85 kPa,
and the sample was loaded to ultimate
conditions. A pore pressure of 55 kPa was
measured at ultimate state. What value of
major principal total stress was measured at
the ultimate state?
A consolidated drained (CD) triaxial test was carried out on a normally consolidated clay. The specimen was consolidated under a cell pressure of 100 kPa and back pressure of 30 kPa. The axial deviatoric stress was increased very slowly to failure, so that there was no excess pore water pressure developed during the shearing. The specimen failed under a deviatoric stress of 130 kPa. The back pressure of 30 kPa was maintained throughout the test.
(i) What is the friction angle in terms of effective stresses? (ii) What are the shear stress and normal stress acting on the failure plane?
Solution fast please
A consolidated drained (CD) triaxial test was carried out on a normally consolidated clay. The specimen was consolidated under a cell pressure of 100 kPa and back pressure of 30 kPa. The axial deviatoric stress was increased very slowly to failure, so that there was no excess pore water pressure developed during the shearing. The specimen failed under a deviatoric stress of 130 kPa. The back pressure of 30 kPa was maintained throughout the test.
(1) What is the friction angle in terms of effective stresses?
(ii) What are the shear stress and normal stress acting on the failure plane?
Chapter 10 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 10 - Prob. 10.1PCh. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Prob. 10.10P
Ch. 10 - Prob. 10.11PCh. 10 - Prob. 10.12PCh. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Prob. 10.15PCh. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - Prob. 10.23PCh. 10 - Prob. 10.24CTPCh. 10 - Prob. 10.25CTP
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- Tri-Axial Testsarrow_forward5. A consolidated, undrained triaxial test is being caried out on a normally consolidated clay where c = 0 and 41= 26'. The triaxial specimen was consolidated under a cell pressure of 300 kPa and backpressure of 80 kPa. Skempton's A parameter at failure is estimated to be 0.80. The drainage valve has since been dosed and the vertical deviator stress increased to failure. What would be the deviator stress and pore water pressure at failure?arrow_forwardThe results below were obtained at failure in a series of consolidated-untrained triaxial tests, with pore water pressure measurement, on specimens of a fully saturated clay. Determine the values of the shear strength parameters c' and 'If a specimen of the same soil were consolidated under an all-round pressure of 300 kN/m² and the principal stress difference applied with the all-round pressure changed to 400kN/m², what would be the expected value of principal stress difference at failure" 150 300 450 600 03 (kN/m²) 01-03 (kN/m²) u (kN/m²) 103 202 305 410 82 169 252 331arrow_forward
- A drained triaxial compression test on a saturated clay yielded the effective shear strength parameters as c' = 15 kPa and o'= 22°. %3D Consolidated Undrained triaxial test on an identical sample of this clay at a cell pressure of 200 kPa developed a pore water pressure of 150 kPa at failure. The deviator stress (expressed in kPa) at failure isarrow_forwardA consolidated-undrained triaxial test was conducted on a dense sand with a chamber-confining pressure of 20 lb/in?. Results showed that o' = 24° and o = 31°. Determine the deviator stress and the pore water pressure at failure.arrow_forwardA triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively. a. Determine the angle of internal friction of the sand? b. Determine the angle of the failure plane? c. Determine the maximum principal stress? Please answer this asap. For upvote. Thank you very mucharrow_forward
- a consolidated tri-axial test was conducted on a normally consolidated clay. the results were as follows: chamber confining pressure = 316 kPa, deviator stress = 424 kPa. compute for the shear stress on the failure plane in kPa.arrow_forward5. A consolidated, undrained triaxial test is being carried out on a normally consolidated clay where c - 0 and p'= 26'. The triaxial specimen was consolidated under a cell pressure of 300 kPa and backpressure of 80 kPa. Skempton's A parameter at failure is estimated to be 0.80. The drainage valve has since been dosed and the vertical deviator stress increased to failure. What would be the deviator stress and pore water pressure at failure?arrow_forwardIn a triaxial test, a specimen of saturated [normally consolidated] clay was consolidated under a chamber confining pressure of 80 kPa. The axial stress on the specimen was then increased through the allowing the drainage from the specimen. The specimen fails when 120 kPa. The pore water pressure at the time was 50 kPa. What is the consolidated undrained friction angle [phi]?arrow_forward
- B) The results below were obtained at failure in a series of consolidated-undrained triaxial tests, with pore water pressure measurement, on specimens of a fully saturated clay. Determine the values of the shear strength parameters c' and q'. If a specimen of the same soil were consolidated under an all-round pressure of 240 kN/m² and the principal stress difference applied with the all-round pressure changed to 340 kN/m², what would be the expected value of principal stress difference at failure? Table 1: Results of CUT tests. 150 300 450 105 205 310 85 170 250 03, kPa 01-03, kPa u, kPa 600 420 330arrow_forwardFoundation: Direct Shear Testarrow_forwardA soft clay in an unconfined compression test did not develop a failure plane but bulged during the test. The sample was 40 mm in diameter and 85 mm in length. The load carried at a strain of 15% was 70.4 N. Determine the shear strength.arrow_forward
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