Engineering Electromagnetics
9th Edition
ISBN: 9781260029963
Author: Hayt
Publisher: MCG
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Chapter 10, Problem 10.6P
A
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Design a counter to count-up from 2 to 7 using three of
D Flip Flops
(3) 3-Bit Count up (3 to 5) Using D Flip-Flop:
The State Equation of D Flip-Flop:
Q(t+1)=D(t) => Dn=Qn
Present State
D Flip-Flop
Next State
n
Q2p Q1p Q0p
3
0 1
1
1
Q2n Q1n Q0n D2 D1 D0
0 0 1 0 0
4
1
0
0
1
0
1
1 0
1
5
1 0
1
0
1
1
01
1
D2-Sum(3,4) and don't care X-Sum(0,1,2,6,7)
D1=Sum(5) and don't care X=Sum(0,1,2,6,7)
D0=Sum(4,5) and don't care X=Sum(0,1,2,6,7)
Using K-map to simplify the functions:
D2=Q1+Q0'
D1=Q1'QO
DO=Q1'
XOX
XOX
Q2 10
Q2 01
Q2 1xx
Q0
QO
Qo
D2 Q2
>CK
Q2
D1 Q1
BCD
CK
Q1
DO QF
►CK
Q0
☐ Present State Next State D Flip-Flop
n Q2p Q1p Q0p Q2n Q1n Q0n D2 D1 D0
2 0 1
0
0 1 1 0 1 1
3 0
1
1
1
0
0 1 00
4
1
0
0
1
0
1
1
0
1
5
1
0
1
1
1
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1 1
0
6
1
1
0
0
1
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1
0
D2
D2=Sum(3,4,5), X=Sum(0,1,7)
D1
Q2
1
Q1
1
0
☑
0
Qo
D2=Q0+Q1'
✗
0
Q1
Consider the following 4×1 multiplexer with inputs:
w0=2, w1=1, w2=x2' and w3=0
And with switches:
S1 x1 and S0=x0
What is the multiplexer output f as a function of x2, x1
and x0?
I need help adding a capacitor and a Zener diode to my circuit. I’m looking for a simple sketch or diagram showing how to connect them. i want diagram with final circuit after adding the zener diad and capacitor. don't do calclution or anything. thanks
Chapter 10 Solutions
Engineering Electromagnetics
Ch. 10 - The parameters of a certain transmission line...Ch. 10 - A sinusoidal wave on a transmission line is...Ch. 10 - Prob. 10.3PCh. 10 - A sinusoidal voltage V0, frequency , and phase...Ch. 10 - Two voltage waves of equal amplitude V0 and radian...Ch. 10 - A 50 load is attached to a 50-m section of the...Ch. 10 - Prob. 10.7PCh. 10 - An absolute measure of power is the dBm scale, in...Ch. 10 - A 100-m transmission line is used to propagate a...Ch. 10 - Two lossless transmission lines having different...
Ch. 10 - Two voltage waves of equal amplitude V0, which...Ch. 10 - In a circuit in which a sinusoidal voltage source...Ch. 10 - The skin effect mechanism in transmission lines is...Ch. 10 - A lossless transmission line having characteristic...Ch. 10 - Figure 10.29 See Problem 10.15. For the...Ch. 10 - A 100 lossless transmission line is connected to a...Ch. 10 - Determine the average power absorbed by each...Ch. 10 - The line shown in Figure 10.31 is lossless. Find s...Ch. 10 - A lossless transmission line is 50 cm in length...Ch. 10 - (a) Determine s on the transmission line of Figure...Ch. 10 - Prob. 10.21PCh. 10 - Prob. 10.22PCh. 10 - The normalized load on a lossless transmission...Ch. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - A 75 lossless line is of length 1.2 . It is...Ch. 10 - Prob. 10.27PCh. 10 - The wavelength on a certain lossless line is 10...Ch. 10 - Prob. 10.29PCh. 10 - A two-wire line constructed of lossless wire of...Ch. 10 - In order to compare the relative sharpness of the...Ch. 10 - In Figure 10.17, let ZL=250 and Z0=50. Find the...Ch. 10 - In Figure 10.17, let ZL=100+j150 and Z0=100. Find...Ch. 10 - The lossless line shown in Figure 10.35 is...Ch. 10 - Prob. 10.35PCh. 10 - The two-wire lines shown in Figure 10.36 are all...Ch. 10 - Prob. 10.37PCh. 10 - Repeat Problem 10.37, with, Z0=50 and RL=Rg=25....Ch. 10 - In the transmission line of Figure 10.20, Z0=50,...Ch. 10 - In the charged line of Figure 10.25, the...Ch. 10 - In the transmission line of Figure 10.37, the...Ch. 10 - Figure 10.38 See Problem 10.42. A simple frozen...Ch. 10 - Figure 10.39 See Problem 10.43. In Figure 10.39,...
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- Question 3 AC Motor Drives [15]Calculate the instantaneous currents delivered by the inverter if the direct axiscurrent required at a particular instant is 8.66A and the quadrature current is5A. Derive all equations for the three currents.arrow_forwardA certain signal f(t) has the following PSD (assume 12 load): Sp (w) = new + 8(w) - 1.5) + (w + 1.5)] (a) What is the mean power in the bandwidth w≤2 rad/see? (b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec? Paress(w) dw 2ㅈ -arrow_forward(75 Marks) JA signal (t) is bond 7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be limited to 9.6 kHz, and three other signals transmitted by means of time-division multiplexing. Set up scheme for accomplishing this multiplexing requirement, with each signal sampled at its Nyquist rate. What must be the speed of the commutator (the output but ram-k bit/sec)? the minimum band width? (25 Marks)arrow_forward
- Draw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown 101 wwwwwwwwwwww 010 BASESAND basband CARRIER Carralarrow_forwardplease show full working. I've included the solutionarrow_forwardcan you please show working and steps. The answer is 8kohms.arrow_forward
- PSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forwardAn AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forward
- Can you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forward
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