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Concept explainers
(a)
Interpretation:
The molecular formula of lactic acid should be determined.
Concept Introduction:
The molecular formula of any molecule explains about the atoms present in it along with the numbers of atoms.
(b)
Interpretation:
The
Concept Introduction:
The functional groups are the atoms or groups of atom which undergoes some chemical transformation in organic molecules. These chemical transformations are very important part of organic compounds because of these functional units, organic compounds are divided.
(c)
Interpretation:
The bond angles of carbon atoms of Lactic acid should be identified.
Concept Introduction:
The bond angles are angles occurring in between the bonds forming atoms of molecules. This bond angles can be determined with the help of VSEPR model that shows the regions of electron density around the atoms.
(d)
Interpretation:
The polar and nonpolar bonds of lactic acid should be identified.
Concept Introduction:
Polar bonds are bonds in which electronegativity difference of atoms is in range of 0.5 and 1.4. Nonpolar bonds are bonds with electronegativity difference of less than 0.5.
(e)
Interpretation:
The polarity of lactic acid molecule should be identified.
Concept Introduction:
Polarity of any molecule depends on electronegativity of atoms that forms covalent bonds. Depending upon the difference in electronegativity of atoms, polar or nonpolar molecule is determined. Polar molecule has electronegativity between 0.5 and 1.4 whereas in nonpolar molecule, it is less than 0.5.
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Chapter 10 Solutions
Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
- Q: Draw the molecular orbital energy level diagram for the following molecules. 1- The SF4 molecule is seesaw molecular geometry and has C2v point group. 2- The Mn(CO)s molecule with C4v point group is square pyramidal.arrow_forwardPlease correct answer and don't use hand ratingarrow_forwardwhen a 0.150 g sample of the compound was burned, it produced 0.138 g CO2 & 0.0566 g H2O. All the nitrogen in a different 0.200 g sample of the compound was converted to NH3, which was found to weigh 0.0238 g. Finally, the chlorine in a 0.125 g sample of the compound was converted to Cl- and by reacting it with AgNO3, all of the chlorine was recovered as the solid AgCl. The AgCl, when dried was found to weigh 0.251 g. What is the empirical formulaarrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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