Give the IUPAC name for each compound. a. c. e. b. d. f.

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 10, Problem 10.38P

Give the IUPAC name for each compound.

a. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 1 c. e.

b. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 4 d. f.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Expert Solution

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Expert Solution

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.

Conclusion

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

(3 pts) Use the Kapustinskii equation to calculate the lattice enthalpy for MgBr2 anddiscuss any differences between this result and that from #4.

(3 pts) Silver metal adopts a fcc unit cell structure and has an atomic radius of 144 pm. Fromthis information, calculate the density of silver. Show all work.

4. (3 pts) From the information below, determine the lattice enthalpy for MgBr2. Show all work. AH/(kJ mol-¹) Sublimation of Mg(s) +148 lonization of Mg(g) +2187 to Mg2+(g) Vaporization of Br₂(1) +31 Dissociation of Br,(g) +193 Electron gain by Br(g) -331 Formation of MgBr₂(s) -524

Answer 2

Textbook Question

Chapter 10, Problem 10.38P

Give the IUPAC name for each compound.

a. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 1 c. e.

b. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 4 d. f.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Expert Solution

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Expert Solution

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.

Conclusion

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 10, Problem 10.38P

Give the IUPAC name for each compound.

a. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 1 c. e.

b. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 4 d. f.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Expert Solution

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Expert Solution

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.

Conclusion

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 10, Problem 10.38P

Give the IUPAC name for each compound.

a. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 1 c. e.

b. Chapter 10, Problem 10.38P, Give the IUPAC name for each compound. a. c. e. b. d. f. , example 4 d. f.

Expert Solution

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Expert Solution

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Expert Solution

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.

Conclusion

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Expert Solution

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Expert Solution

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Expert Solution

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Expert Solution

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Expert Solution

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.

Conclusion

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene

Answer 8

Expert Solution

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

(a)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer 13

Answer to Problem 10.38P

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Answer 14

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 1

Figure 1

The numbering of carbon atoms present in the longest carbon chain is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 2

Figure 2

The longest carbon chain has nine carbon atoms. The root word used for nine carbon atoms is non and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the third carbon atom and one isopropyl substituents is attached to the sixth carbon atom. The double bond is present between third and fourth carbon atom.Thus, the IUPAC name of the given structure is 6−isopropyl−3−methylnon−3−ene.

Answer 15

Conclusion

The IUPAC name for the given compound is 6−isopropyl−3−methylnon−3−ene.

Answer 16

Expert Solution

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Interpretation Introduction

(b)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer 21

Answer to Problem 10.38P

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Answer 22

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 3

Figure 3

The numbering of carbon atoms present in longest chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 4

Figure 4

The longest carbon-carbon chain has five carbon atoms. The root word used for five carbon atoms is pent and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituent is attached to the second carbon atom and one methyl substituent is attached to the fourth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 2−isopropyl−4−methylpent−1−ene.

Answer 23

Conclusion

The IUPAC name for the given compound is 2−isopropyl−4−methylpent−1−ene.

Answer 24

Expert Solution

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Interpretation Introduction

(c)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer 29

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Answer 30

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 5

Figure 5

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 6

Figure 6

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituents is attached to the first carbon atom and two methyl substituents are attached to the third carbon atom. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Thus, the IUPAC name of the given structure is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Answer 31

Conclusion

The IUPAC name for the given compound is 5−(sec−butyl)−1,3,3−trimethylcyclohex−1−ene.

Answer 32

Expert Solution

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Interpretation Introduction

(d)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer 37

Answer to Problem 10.38P

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol

Answer 38

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 7

Figure 7

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 8

Figure 8

The longest carbon chain has seven carbon atoms. The root word used for seven carbon atoms is hept and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One isopropyl substituents is attached to the fourth carbon atom. The double bond is present between fourth and fifth carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 4−isopropylhept−4−ene−3−ol.

Answer 39

Conclusion

The IUPAC name for the given compound is 4−isopropylhept−4−ene−3−ol.

Answer 40

Expert Solution

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Answer 41

Expert Solution

Answer 42

Expert Solution

Answer 43

Expert Solution

Answer 44

Interpretation Introduction

(e)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer 45

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Answer 46

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 9

Figure 9

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 10

Figure 10

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One secondary butyl substituent is attached to the fifth carbon atom. The double bond is present between first and second carbon atom. Another functional group present in the given structure is alcohol (−OH). The suffix used for alcohol is –ol. Thus, the IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Answer 47

Conclusion

The IUPAC name of the given structure is 5−(sec−butyl)cyclohex-2-ene−1−ol.

Answer 48

Expert Solution

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.

Conclusion

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene

Answer 49

Expert Solution

Answer 50

Expert Solution

Answer 51

Expert Solution

Answer 52

Interpretation Introduction

(f)

Interpretation: The IUPAC name for the given compound is to be stated.

Concept introduction: The systematic naming of organic compound is given by IUPAC nomenclature. The naming of organic compound is done such that the structure of organic compound is correctly interpreted from the name.

Rules for writing IUPAC name from structural formula are

1. First identify the longest carbon chain.

2. The next step is to identify the groups attached to the longest chain.

3. Identify the position, location, and number of the substituent bonded to the carbon chain.

4. Use prefix di, tri, tetra if same type of substituent is present.

5. Name the substituents in alphabetical order.

Answer 53

Answer to Problem 10.38P

The IUPAC name for the given compound is 5−ethyl−3,4dimethylnon−2−ene.

Answer 54

Explanation of Solution

The given compound is,

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 11

Figure 11

The numbering of carbon atoms present in longest carbon chain of the given compound is shown below.

Organic Chemistry, Chapter 10, Problem 10.38P , additional homework tip 12

Figure 12

The longest carbon chain has six carbon atoms. The root word used for six carbon atoms is hex and the suffix used for C=C linkage is –ene. The hydrocarbons that are attached to the longest chain are called substituents and they are written as prefix in alphabetical order. One methyl substituent is attached to the third and fourth carbon atom. One ethyl substituent is attached to the fifth carbon atom. The double bond is present between second and third carbon atom.. Thus, the IUPAC name of the given structure is 5−ethyl−3,4dimethylnon−2−ene.