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Chapter 10, Problem 10.29P
Interpretation Introduction

(a)

Interpretation: The constitutional isomer formed by the reaction of given alkene with [1] H2O, H2SO4 and [2] BH3 followed by H2O2 is to be predicted.

Concept introduction: The compounds with same chemical formula but different arrangement of atoms in space are known as the constitutional isomer.

Hydration of alkenes is one of the methods used for the formation of alcohol.

Expert Solution
Check Mark

Answer to Problem 10.29P

The constitutional isomer formed by the reaction of given alkene with H2O, H2SO4 is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  1

Figure 1

The constitutional isomer formed by the reaction of given alkene with BH3 followed by H2O2 is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  2

Figure 2

Explanation of Solution

The compounds with same chemical formula but different arrangement of atoms in space are known as the constitutional isomer.

Hydration of alkenes is one of the methods used for the formation of alcohol.

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows Anti-Markovnikov’s rule.

In hydration reactions, the mode of addition is anti-addition, whereas in hydroboration-oxidation, the mode of addition is syn addition.

The given alkene is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  3

Figure 3

The product formed by the reaction of methylenecyclopentane with BH3 followed by H2O2 is shown below.

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  4

Figure 4

The general steps followed by the hydration reaction are stated below:

• First protonation of the alkene take place to generate the carbocation.

• Formation of protonated alcohol.

• Deprotonation.

The product formed by the reaction of methylenecyclopentane with H2O,H2SO4 is shown below.

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  5

Figure 5

Conclusion

The constitutional isomer formed by the reaction of given alkenes with [1] H2O, H2SO4 and [2] BH3 followed by H2O2 is rightfully stated.

Interpretation Introduction

(b)

Interpretation: The constitutional isomer formed by the reaction of given alkenes with [1] H2O, H2SO4 and [2] BH3 followed by H2O2 is to be predicted.

Concept introduction: The compounds with same chemical formula but different arrangement of atoms in space are known as the constitutional isomer.

Hydration of alkenes is one of the methods used for the formation of alcohol.

Expert Solution
Check Mark

Answer to Problem 10.29P

The constitutional isomer formed by the reaction of given alkenes with H2O, H2SO4 is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  6

Figure 6

The constitutional isomer formed by the reaction of given alkenes with BH3 followed by H2O2 is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  7

Figure 7

Explanation of Solution

The compounds with same chemical formula but different arrangement of atoms in space are known as the constitutional isomer.

Hydration of alkenes is one of the methods used for the formation of alcohol.

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows Anti-Markovnikov’s rule.

In hydration reactions, the mode of addition is anti-addition, whereas in hydroboration-oxidation, the mode of addition is syn addition.

The given alkene is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  8

Figure 8

The product formed by the reaction of prop1en2ylcyclhexane with BH3 followed by H2O2 is shown below.

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  9

Figure 9

The general steps followed by the hydration reaction are stated below:

• First protonation of the alkene take place to generate the carbocation.

• Formation of protonated alcohol.

• Deprotonation.

The product formed by the reaction of prop1en2ylcyclhexane with H2O,H2SO4 is shown below.

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  10

Figure 10

Conclusion

The constitutional isomer formed by the reaction of given alkenes with [1] H2O, H2SO4 and [2] BH3 followed by H2O2 is rightfully stated.

Interpretation Introduction

(c)

Interpretation: The constitutional isomer formed by the reaction of given alkene with [1] H2O, H2SO4 and [2] BH3 followed by H2O2 is to be predicted.

Concept introduction: The compounds with same chemical formula but different arrangement of atoms in space are known as the constitutional isomer.

Hydration of alkenes is one of the methods used for the formation of alcohol.

Expert Solution
Check Mark

Answer to Problem 10.29P

The constitutional isomer formed by the reaction of given alkene with H2O, H2SO4 is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  11

Figure 11

The constitutional isomer formed by the reaction of given alkene with BH3 followed by H2O2 is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  12

Figure 12

Explanation of Solution

The compounds with same chemical formula but different arrangement of atoms in space are known as the constitutional isomer.

Hydration of alkenes is one of the methods used for the formation of alcohol.

Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows Anti-Markovnikov’s rule.

In hydration reactions, the mode of addition is anti-addition, whereas in hydroboration-oxidation, the mode of addition is syn addition.

The given alkene is,

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  13

Figure 13

The product formed by the reaction of methylenecyclopentane with BH3 followed by H2O2 is shown below.

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  14

Figure 14

The general steps followed by the hydration reaction are stated below:

• First protonation of the alkene take place to generate the carbocation.

• Formation of protonated alcohol.

• Deprotonation.

The product formed by the reaction of methylenecyclopentane with H2O,H2SO4 is shown below.

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card, Chapter 10, Problem 10.29P , additional homework tip  15

Figure 15

Conclusion

The constitutional isomer formed by the reaction of given alkenes with [1] H2O, H2SO4 and [2] BH3 followed by H2O2 is rightfully stated.

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Chapter 10 Solutions

Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card

Ch. 10 - Linolenic acidTable 10.2 and stearidonic acid are...Ch. 10 - Prob. 10.12PCh. 10 - Problem 10.13 What product is formed when each...Ch. 10 - Prob. 10.14PCh. 10 - Problem 10.15 Draw the products formed when each...Ch. 10 - Prob. 10.16PCh. 10 - Prob. 10.17PCh. 10 - Addition of HBr to which of the following alkenes...Ch. 10 - Problem 10.19 Draw the products, including...Ch. 10 - Prob. 10.20PCh. 10 - Problem 10.21 What two alkenes give rise to each...Ch. 10 - Prob. 10.22PCh. 10 - Problem 10.23 Draw the products of each reaction,...Ch. 10 - Problem 10.24 Draw all stereoisomers formed in...Ch. 10 - Prob. 10.25PCh. 10 - Problem 10.26 What alkylborane is formed from...Ch. 10 - Draw the products formed when each alkene is...Ch. 10 - What alkene can be used to prepare each alcohol as...Ch. 10 - Prob. 10.29PCh. 10 - Draw the products of each reaction using the two...Ch. 10 - Problem 10.31 Devise a synthesis of each compound...Ch. 10 - Give the IUPAC name for each compound. a.b.Ch. 10 - a Label the carbon-carbon double bond in A as E or...Ch. 10 - Prob. 10.34PCh. 10 - 10.35 Calculate the number of degrees of...Ch. 10 - Prob. 10.36PCh. 10 - Label the alkene in each drug as E or Z....Ch. 10 - Give the IUPAC name for each compound. a. c. e. b....Ch. 10 - Prob. 10.39PCh. 10 - 10.40 (a) Draw all possible stereoisomers of, and...Ch. 10 - Prob. 10.41PCh. 10 - 10.42 Now that you have learned how to name...Ch. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Draw the products formed when (CH3)2C=CH2 is...Ch. 10 - What alkene can be used to prepare each alkyl...Ch. 10 - Prob. 10.48PCh. 10 - Draw the constitutional isomer formed in each...Ch. 10 - Prob. 10.50PCh. 10 - Draw all stereoisomers formed in each reaction. a....Ch. 10 - Draw the products of each reaction, including...Ch. 10 - Prob. 10.53PCh. 10 - Prob. 10.54PCh. 10 - Prob. 10.55PCh. 10 - 10.56 Draw a stepwise mechanism for the following...Ch. 10 - Prob. 10.57PCh. 10 - Draw a stepwise mechanism for the conversion of...Ch. 10 - Draw a stepwise mechanism that shows how all three...Ch. 10 - Less stable alkenes can be isomerized to more...Ch. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Bromoetherification, the addition of the elements...Ch. 10 - Devise a synthesis of each product from the given...Ch. 10 - 10.65 Draw a synthesis of each compound from...Ch. 10 - 10.66 Explain why A is a stable compound but B is...Ch. 10 - Prob. 10.67PCh. 10 - Prob. 10.68PCh. 10 - 10.69 Lactones, cyclic esters such as compound A,...Ch. 10 - 10.70 Draw a stepwise mechanism for the following...Ch. 10 - 10.71 Like other electrophiles, carbocations add...Ch. 10 - 10.72 Draw a stepwise mechanism for the...
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